• MySQL根据某一个或者多个字段查找重复数据的sql语句


    1.表中有id和name 两个字段,查询出name重复的所有数据

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    select * from xi a where (a.username) in (select username from xi group by username having count(*) > 1)

    2、查询出所有数据进行分组之后,和重复数据的重复次数的查询数据,先列下:

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    select count(username) as '重复次数',username from xi group by username having count(*)>1 order by username desc

    3、一下为 查看别人的 结果,现列下:查询及删除重复记录的方法大全

    1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断

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    select * from people
    where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)

    2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录

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    delete from people
    where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
    and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)

    3、查找表中多余的重复记录(多个字段)

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    select * from vitae a
    where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)

    4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录

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    delete from vitae a
    where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
    and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

    5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录

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    select * from vitae a
    where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
    and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

    (二)

    比方说

    在A表中存在一个字段“name”,

    而且不同记录之间的“name”值有可能会相同,

    现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;

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    Select Name,Count(*) From A Group By Name Having Count(*) > 1

    如果还查性别也相同大则如下:

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    Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1

    (三)

    方法一

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    declare @max integer,@id integer
    declare cur_rows cursor local for
    select 主字段,count(*) from 表名 group by 主字段 having count(*) >;
    open cur_rows fetch cur_rows into @id,@maxwhile @@fetch_status=0
    begin
     select @max = @max -1
     set rowcount @max
     delete from 表名 where 主字段 = @id
    fetch cur_rows into @id,@maxend
    close cur_rows
    set rowcount 0

    方法二"重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。

      1、对于第一种重复,比较容易解决,使用

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    select distinct * from tableName

    就可以得到无重复记录的结果集。  

    如果该表需要删除重复的记录(重复记录保留1条),

    可以按以下方法删除

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    select distinct * into #Tmp from tableName
    drop table tableName
    select * into tableName from #Tmp
    drop table #Tmp

    发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。

    2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下  假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集

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    select identity(int,1,1) as autoID, * into #Tmp from tableName
    select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID
    select * from #Tmp where autoID in(select autoID from #tmp2) 

    最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)

    (四)查询重复

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    select * from tablename where id in (select id from tablenamegroup by idhaving count(id) > 1)

    对一个字段查找重复记录

    根据sample_code字段找到重复记录

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    SELECT * FROM tb_table WHERE sample_code IN( SELECT sample_code FROM tb_table GROUP BY sample_code HAVING COUNT(sample_code) > 1 );

    对多个字段查找重复记录(这里以2个为例)

    根据name和code字段找到重复记录

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    SELECT * from (SELECT *, CONCAT(name,code) as nameAndCode from tb_table) t WHERE t.nameAndCode in
    (
     SELECT nameAndCode from (SELECT CONCAT(name,code) as nameAndCode from tb_table) tt GROUP BY nameAndCode HAVING count(nameAndCode) > 1
    )

    多字段查,删

    SELECT * FROM vip_goodsdiscount WHERE (goodsId,cardType) IN (SELECT goodsId,cardType FROM vip_goodsdiscount GROUP BY goodsId,cardType HAVING COUNT(*) > 1)
    ORDER BY goodsId DESC

    DELETE FROM vip_goodsdiscount
    WHERE (vip_goodsdiscount.goodsId,vip_goodsdiscount.cardType) IN (SELECT * FROM (SELECT goodsId,cardType FROM vip_goodsdiscount GROUP BY goodsId,cardType HAVING COUNT(*) > 1) AS t1 )
    AND id NOT IN (SELECT * FROM (SELECT MIN(id) FROM vip_goodsdiscount GROUP BY goodsId,cardType HAVING COUNT(*)>1) AS t2)

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  • 原文地址:https://www.cnblogs.com/zhangzhiping35/p/12066930.html
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