• [IOI2008]Island


    题目地址


    思路:

    • 无向基环树森林求直径和。
    • 对于每颗基环树,它对答案的贡献只有可能经过环或不经过,分类讨论即可。
    • 首先处理出每个点往下的最大深度,顺便进行树形DP,再用单调队列获取经过环时的答案即可。
    • 最终树形DP与单调队列的结果取max即可。
    • (注意内存,数组需要使用技巧二次利用)

     (该代码内存超限)

    #pragma GCC diagnostic error "-std=c++14"
    #pragma GCC optimize ("O3")
    #include<cstdio>
    #include<iostream>
    #include<queue>
    #include<vector>
    #include<cstring>
    using namespace std;
    const int MAXN=2000020,MAXM=1000010;
    int n;
    struct Edge{
        int from,to,w,nxt;
    }e[MAXN];
    int head[MAXN],edgeCnt=1,degree[MAXN];
    void addEdge(int u,int v,int w){
        e[++edgeCnt].from=u;
        e[edgeCnt].to=v;
        e[edgeCnt].w=w;
        e[edgeCnt].nxt=head[u];
        head[u]=edgeCnt;
    }
    queue<int> topoQueue;
    void topoSort(){
        for(int i=1;i<=n;i++)if(degree[i]==1)topoQueue.push(i);
        while(!topoQueue.empty()){
            int nowV=topoQueue.front();topoQueue.pop();
            for(int i=head[nowV];i;i=e[i].nxt){
                int v=e[i].to;
                degree[v]--,degree[nowV]--;
                if(degree[v]==1)topoQueue.push(v);
            }
        }
    }
    bool First_vis_circle[MAXN];
    deque<int> First_circles[MAXN];int First_circleCnt=0;
    long long First_dist[MAXN];
    void First_find_Circle(int x,long long dis){
        First_vis_circle[x]=1;
        First_dist[x]=dis;
        First_circles[First_circleCnt].push_back(x);
        for(int i=head[x];i;i=e[i].nxt){
            int v=e[i].to;
            if(!First_vis_circle[v]&&degree[v]>=2){
                First_find_Circle(v,e[i].w+dis);
            }
        }
    }
    bool Second_vis_circle[MAXN];
    long long Second_dist[MAXN];
    deque<int> Second_circles[MAXN];int Second_circleCnt=0;
    void Second_find_Circle(int x,long long dis,bool isFirst){
        Second_vis_circle[x]=1;
        Second_dist[x]=dis;
        Second_circles[Second_circleCnt].push_back(x);
        for(int i=head[x];i;i=e[i].nxt){
            int v=e[i].to;
            if(!Second_vis_circle[v]&&degree[v]>=2){
                if(isFirst){
                    isFirst=false;
                    continue;
                }
                Second_find_Circle(v,e[i].w+dis,0);
            }
        }
    }
    long long d[MAXN];
    bool vis_dp[MAXN];
    long long ans[MAXN],nowRoot=0;
    long long circle_deep_ans[MAXN]; 
    void dfs_dp(int x,int in_edge,int in_circle){
        vis_dp[x]=1;
        for(int i=head[x];i;i=e[i].nxt){ 
            if(i==(in_edge^1))continue;
            int v=e[i].to;
            if(degree[v]<2&&(!vis_dp[v])){
                dfs_dp(v,i,in_circle);
                ans[x]=max(ans[x],d[x]+d[v]+e[i].w);
                circle_deep_ans[in_circle]=max(circle_deep_ans[in_circle],
                ans[x]);
                d[x]=max(d[x],d[v]+e[i].w);
            }
        }
    }
    int First_a[MAXN],First_endIndex=0;
    int First_q[MAXN];
    long long First_ans_point_to_point[MAXN],First_ans_point_to_pointCnt=0;
    int Second_a[MAXN],Second_endIndex=0;
    int Second_q[MAXN];
    long long Second_ans_point_to_point[MAXN],Second_ans_point_to_pointCnt=0;
    long long across_ans[MAXN];//直径 
    long long total_across_ans=0;
    int main(){
        memset(across_ans,0xcf,sizeof(across_ans));
        scanf("%d",&n);
        for(int i=1;i<=n;i++){
            int v,w;
            scanf("%d%d",&v,&w);
            addEdge(i,v,w);
            addEdge(v,i,w);
            degree[v]++;degree[i]++;
        }
        topoSort();
        for(int i=1;i<=n;i++){
            if(!First_vis_circle[i]&&degree[i]>=2){
                First_circleCnt++;
                First_find_Circle(i,0);
            }
        }
        for(int i=1;i<=n;i++){
            if(!Second_vis_circle[i]&&degree[i]>=2){
                Second_circleCnt++;
                Second_find_Circle(i,0,1);
            }
        }
        for(int i=1;i<=First_circleCnt;i++){
            int first=First_endIndex+1,size=First_circles[i].size();
            First_endIndex=first+2*size-1;
            int nowIndex=first;
            while(!First_circles[i].empty()){
                int nowV=First_circles[i].front();First_circles[i].pop_front();
                dfs_dp(nowV,0,i);
                First_a[nowIndex]=nowV;
                First_a[nowIndex+size]=nowV;
                nowIndex++;
                First_endIndex=nowIndex;
            }
            int l,r;
            First_q[l=r=1]=first;
            First_ans_point_to_pointCnt++;
            for(int j=first+1;j<=First_endIndex;j++){
                while(l<r&&j-First_q[l]>=size)l++;
                First_ans_point_to_point[First_ans_point_to_pointCnt]=max(First_ans_point_to_point[First_ans_point_to_pointCnt],
                d[First_a[j]]+d[First_a[First_q[l]]]+First_dist[First_a[j]]-First_dist[First_a[First_q[l]]]);
                while(l<r&&d[First_q[r]]-First_dist[First_q[r]]<
                d[First_a[j]]-First_dist[First_a[j]])r--;
                First_q[++r]=j;
            }
        }
        for(int i=1;i<=Second_circleCnt;i++){
            int first=Second_endIndex+1,size=Second_circles[i].size();
            Second_endIndex=first+2*size-1;
            int nowIndex=first;
            while(!Second_circles[i].empty()){
                int nowV=Second_circles[i].front();Second_circles[i].pop_front();
                dfs_dp(nowV,0,i);
                Second_a[nowIndex]=nowV;
                Second_a[nowIndex+size]=nowV;
                nowIndex++;
                Second_endIndex=nowIndex;
            }
            int l,r;
            Second_q[l=r=1]=first;
            Second_ans_point_to_pointCnt++;
            for(int j=first+1;j<=Second_endIndex;j++){
                while(l<r&&j-Second_q[l]>=size)l++;
                Second_ans_point_to_point[Second_ans_point_to_pointCnt]=max(Second_ans_point_to_point[Second_ans_point_to_pointCnt],
                d[Second_a[j]]+d[Second_a[Second_q[l]]]+Second_dist[Second_a[j]]-Second_dist[Second_a[Second_q[l]]]);
                while(l<r&&d[Second_a[Second_q[r]]]-Second_dist[Second_a[Second_q[r]]]<d[Second_a[j]]-Second_dist[Second_a[j]])r--;
                Second_q[++r]=j;
            }
        }
        
        for(int i=1;i<=First_ans_point_to_pointCnt;i++){
            across_ans[i]=max(across_ans[i],First_ans_point_to_point[i]);
        }
        long long trueAns=0;
        for(int i=1;i<=Second_ans_point_to_pointCnt;i++){
            across_ans[i]=max(across_ans[i],Second_ans_point_to_point[i]);
            trueAns+=max(across_ans[i],circle_deep_ans[i]);
        }
        cout<<trueAns<<endl;
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/zbsy-wwx/p/11680630.html
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