【UVA】1449-Dominating Patterns（AC自己主动机）

AC自己主动机的模板题。须要注意的是，对于每一个字符串，须要利用map将它映射到一个结点上，这样才干按顺序输出结果。

14360841

1449

Dominating Patterns

Accepted

C++

0.146

2014-10-16 11:41:35

#include<stack>
#include<queue>
#include<map>
#include<set>
#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
using namespace std;
const int maxn = 150 * 75;
const int len  = 1111111;
const int max_size = 26;
char str[155][75];
char _str[len];
struct Trie{ //AC
    int tr[maxn][max_size];
    int fail[maxn];
    int val[maxn];     //结果
    int sz,root,_max;  //出现次数
    map<int,int>countx;//计算第i个字符串出现的次数
    map<string,int>vis;
    int index(char c){
        return c - 'a';
    }
    int newnode(){
        val[sz] = 0;
        for(int i = 0; i < 26; i++) tr[sz][i] = -1;
        sz ++;
        return sz - 1;
    }
    void init(){
        sz = 0;_max = 0;
        root = newnode();
        countx.clear();
        vis.clear();
    }
    void insert(char *s,int id){
         int u = root;
         int n = strlen(s);
         for(int i = 0; i < n; i++){
              int c = index(s[i]);
              //printf("%d %d
",u,c);
              if(tr[u][c] == -1)
                   tr[u][c] = newnode();
              u = tr[u][c];
         }
         vis[string(s)] = u; //这个字符串相应的结点编号
         //printf("%d
",u);
         val[u] ++;//达到这个结点的单词
    }
    void build(){
        queue<int>q;
        fail[root] = root;
        for(int i = 0; i < 26; i++){
            if(tr[root][i] == -1)
               tr[root][i] = root;
            else{
                fail[tr[root][i]] = root;
                q.push(tr[root][i]);
            }
        }
        while(!q.empty()){
            int now = q.front(); q.pop();
            for(int i = 0; i < 26; i++){
                if(tr[now][i] == -1)
                    tr[now][i] = tr[fail[now]][i];
                else{
                    fail[tr[now][i]] = tr[fail[now]][i];
                    q.push(tr[now][i]);
                }
            }
        }
    }
    void countt(char *s){
        int n = strlen(s);
        int u = root;
        for(int i = 0; i < n; i++){
            u = tr[u][index(s[i])];
            int temp = u;
            while(temp != root){
                if(val[temp]){           //这个结点存在单词
                    countx[temp]++;      //这个结点
                    _max = max(_max,countx[temp]);
                }
                temp = fail[temp];
            }
        }
    }
};
Trie ac;
int main(){
    int n;
    while(scanf("%d",&n) && n){
        ac.init();
        for(int i = 0; i < n; i++){
            scanf("%s",str[i]);
            ac.insert(str[i],i); //插入单词
        }
        //printf("%d
",ac.sz);
        ac.build();
        scanf("%s",_str);
        ac.countt(_str);
        printf("%d
",ac._max);
        for(int i = 0; i < n; i++){
            if(ac.countx[ac.vis[string(str[i])]] == ac._max)
               printf("%s
",str[i]);
        }
    }
    return 0;
}