• LeetCode: Word Break II


    难题

     1 class Solution {
     2 public:
     3     void dfs(string s, vector<string> &tmp, vector<string> &res, unordered_set<string> &unused, unordered_set<string> &dict) {
     4         if (s.size() == 0) {
     5             string ans = "";
     6             for (int i = 0; i < tmp.size(); i++) {
     7                 if (i == 0) ans += tmp[i];
     8                 else ans += " " + tmp[i];
     9             }
    10             res.push_back(ans);
    11             return;
    12         }
    13         if (unused.find(s) != unused.end()) return;
    14         int pre = res.size();
    15         for (int i = 1; i <= s.size(); i++) {
    16             if (dict.find(s.substr(0, i)) != dict.end()) {
    17                 tmp.push_back(s.substr(0, i));
    18                 dfs(s.substr(i, s.size()-i), tmp, res, unused, dict);
    19                 tmp.pop_back();
    20             }
    21         }
    22         if (res.size() == pre) unused.insert(s);
    23     }
    24     vector<string> wordBreak(string s, unordered_set<string> &dict) {
    25         vector<string> res;
    26         unordered_set<string> unused;
    27         vector<string> tmp;
    28         dfs(s, tmp, res, unused, dict);
    29         return res;
    30     }
    31 };

     C#

     1 public class Solution {
     2     public List<string> WordBreak(string s, ISet<string> wordDict) {
     3         List<string> ans = new List<string>();
     4         HashSet<string> unused = new HashSet<string>();
     5         List<string> tmp = new List<string>();
     6         dfs(s, ref tmp, ref ans, ref unused, wordDict);
     7         return ans;
     8     }
     9     public void dfs(string s, ref List<string> tmp, ref List<string> ans, ref HashSet<string> unused, ISet<string> wordDict) {
    10         if (s.Length == 0) {
    11             string res = "";
    12             for (int i = 0; i < tmp.Count; i++) {
    13                 if (i == 0) res += tmp[i];
    14                 else res += " " + tmp[i];
    15             }
    16             ans.Add(res);
    17             return;
    18         }
    19         if (unused.Contains(s) == true) return;
    20         int pre = ans.Count;
    21         for (int i = 1; i <= s.Length; i++) {
    22             if (wordDict.Contains(s.Substring(0, i))) {
    23                 tmp.Add(s.Substring(0, i));
    24                 dfs(s.Substring(i, s.Length-i), ref tmp, ref ans, ref unused, wordDict);
    25                 tmp.RemoveAt(tmp.Count-1);
    26             }
    27         }
    28         if (ans.Count == pre) unused.Add(s);
    29     }
    30 }
    View Code
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  • 原文地址:https://www.cnblogs.com/yingzhongwen/p/3522292.html
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