• LeetCode: Add Binary


    C++:

     1 class Solution {
     2 public:
     3     string addBinary(string a, string b) {
     4         // Start typing your C/C++ solution below
     5         // DO NOT write int main() function
     6         if (a.size() > b.size()) b = string(a.size()-b.size(), '0') + b;
     7         if (a.size() < b.size()) a = string(b.size()-a.size(), '0') + a;
     8         for (int i = 0; i < a.size(); i++) a[i] += int(b[i]-'0');
     9         int carry = 0;
    10         for (int i = a.size()-1; i >= 0; i--) {
    11             a[i] += carry;
    12             carry = (a[i]-'0') / 2;
    13             if (a[i] > '1') a[i] = '0' + (a[i]-'0') % 2;
    14         }
    15         if (carry) a = '1'+a;
    16         return a;
    17     }
    18 };

    java: 填补短string前面零字符串的操作很烦

     1 public class Solution {
     2     public String addBinary(String a, String b) {
     3         int aLen = a.length();
     4         int bLen = b.length();
     5         for (int i = 0; i < Math.abs(aLen - bLen); i++)
     6         {
     7             if (aLen < bLen)
     8             {
     9                 a = "0" + a;
    10             }
    11             else
    12             {
    13                 b = "0" + b;
    14             }
    15         }
    16         char[] cs1 = a.toCharArray();
    17         char[] cs2 = b.toCharArray();
    18         char[] cs3 = new char[a.length()];
    19         int c = 0;
    20         for (int i = a.length()-1; i >= 0; i--)
    21         {
    22             int tmp = c + (cs1[i] - '0') + (cs2[i] - '0');
    23             c = tmp / 2;
    24             cs3[i] = (char)('0' + tmp % 2);
    25         }
    26         String ans = new String(cs3);
    27         if (c > 0)
    28         {
    29             ans = "1" + ans;
    30         }
    31         return ans;
    32     }
    33 }
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  • 原文地址:https://www.cnblogs.com/yingzhongwen/p/2961295.html
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