• SQL基础练习


    --建表
    --学生表
    CREATE TABLE `Student`(
        `s_id` VARCHAR(20),
        `s_name` VARCHAR(20) NOT NULL DEFAULT '',
        `s_birth` VARCHAR(20) NOT NULL DEFAULT '',
        `s_sex` VARCHAR(10) NOT NULL DEFAULT '',
        PRIMARY KEY(`s_id`)
    );
    --课程表
    CREATE TABLE `Course`(
        `c_id`  VARCHAR(20),
        `c_name` VARCHAR(20) NOT NULL DEFAULT '',
        `t_id` VARCHAR(20) NOT NULL,
        PRIMARY KEY(`c_id`)
    );
    --教师表
    CREATE TABLE `Teacher`(
        `t_id` VARCHAR(20),
        `t_name` VARCHAR(20) NOT NULL DEFAULT '',
        PRIMARY KEY(`t_id`)
    );
    --成绩表
    CREATE TABLE `Score`(
        `s_id` VARCHAR(20),
        `c_id`  VARCHAR(20),
        `s_score` INT(3),
        PRIMARY KEY(`s_id`,`c_id`)
    );
    --插入学生表测试数据
    insert into Student values('01' , '赵雷' , '1990-01-01' , '');
    insert into Student values('02' , '钱电' , '1990-12-21' , '');
    insert into Student values('03' , '孙风' , '1990-05-20' , '');
    insert into Student values('04' , '李云' , '1990-08-06' , '');
    insert into Student values('05' , '周梅' , '1991-12-01' , '');
    insert into Student values('06' , '吴兰' , '1992-03-01' , '');
    insert into Student values('07' , '郑竹' , '1989-07-01' , '');
    insert into Student values('08' , '王菊' , '1990-01-20' , '');
    --课程表测试数据
    insert into Course values('01' , '语文' , '02');
    insert into Course values('02' , '数学' , '01');
    insert into Course values('03' , '英语' , '03');
    
    --教师表测试数据
    insert into Teacher values('01' , '张三');
    insert into Teacher values('02' , '李四');
    insert into Teacher values('03' , '王五');
    
    --成绩表测试数据
    insert into Score values('01' , '01' , 80);
    insert into Score values('01' , '02' , 90);
    insert into Score values('01' , '03' , 99);
    insert into Score values('02' , '01' , 70);
    insert into Score values('02' , '02' , 60);
    insert into Score values('02' , '03' , 80);
    insert into Score values('03' , '01' , 80);
    insert into Score values('03' , '02' , 80);
    insert into Score values('03' , '03' , 80);
    insert into Score values('04' , '01' , 50);
    insert into Score values('04' , '02' , 30);
    insert into Score values('04' , '03' , 20);
    insert into Score values('05' , '01' , 76);
    insert into Score values('05' , '02' , 87);
    insert into Score values('06' , '01' , 31);
    insert into Score values('06' , '03' , 34);
    insert into Score values('07' , '02' , 89);
    insert into Score values('07' , '03' , 98);

    1、查询"01"课程比"02"课程成绩高的学生的信息及课程分数:

    SELECT C.*,D.Cname,D.TId from (SELECT Student.*,SC.CId,SC.score
    FROM
    Student
    Left JOIN
    SC
    ON Student.SId=SC.SId
    WHERE
    Student.SId IN (SELECT A.SID from (SELECT * FROM SC WHERE CId ='01') A,(SELECT * FROM SC WHERE CId='02') B WHERE A.SID =B.SID AND A.SCORE>B.SCORE))
    C LEFT JOIN Course D ON C.CId =D.CId;

    思路:

    1.先查出成绩表SC中01课程的成绩信息,再查出表中02课程的成绩信息

    SELECT * FROM SC WHERE CId ='01';

    SELECT * FROM SC WHERE CId='02';

    2.通过内连接查出两张表sid相同的sid

    SELECT A.SID from (SELECT * FROM SC WHERE CId ='01') A,(SELECT * FROM SC WHERE CId='02') B WHERE A.SID =B.SID AND A.SCORE>B.SCORE;

    3.通过左链接链接Student,SC两表的信息

    SELECT Student.*,SC.CId,SC.score 
    FROM 
    Student 
    Left JOIN 
    SC 
    ON Student.SId=SC.SId 

    4.查询符合条件的学生的信息和课程分数

    SELECT Student.*,SC.CId,SC.score
    FROM
    Student
    Left JOIN
    SC
    ON Student.SId=SC.SId
    WHERE
    Student.SId IN (SELECT A.SID from (SELECT * FROM SC WHERE CId ='01') A,(SELECT * FROM SC WHERE CId='02') B WHERE A.SID =B.SID AND A.SCORE>B.SCORE)

    5.三表联查

    SELECT C.*,D.Cname,D.TId from (SELECT Student.*,SC.CId,SC.score
    FROM
    Student
    Left JOIN
    SC
    ON Student.SId=SC.SId
    WHERE
    Student.SId IN (SELECT A.SID from (SELECT * FROM SC WHERE CId ='01') A,(SELECT * FROM SC WHERE CId='02') B WHERE A.SID =B.SID AND A.SCORE>B.SCORE))
    C LEFT JOIN Course D ON C.CId =D.CId;

    查询结果:

    2.查询平均成绩大于60分的同学的学号和平均成绩;

    select sid,avg(score) from sc group by sid having avg(score)>60;

    3.查询所有同学的学号、姓名、选课数、总成绩;

    SELECT
    A.SID,A.SNAME,B.ss,B.cc 
    FROM 
    (select sid,sname from Student) A
    LEFT JOIN 
    (select sid,SUM(score) ss,count(cid) cc from sc group by sid) B
    WHERE A.SID =B.SID;

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  • 原文地址:https://www.cnblogs.com/yaoze2018/p/12194094.html
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