问题描述:
Design a data structure that supports all following operations in average O(1) time.
insert(val)
: Inserts an item val to the set if not already present.remove(val)
: Removes an item val from the set if present.getRandom
: Returns a random element from current set of elements. Each element must have the same probability of being returned.
Example:
// Init an empty set. RandomizedSet randomSet = new RandomizedSet(); // Inserts 1 to the set. Returns true as 1 was inserted successfully. randomSet.insert(1); // Returns false as 2 does not exist in the set. randomSet.remove(2); // Inserts 2 to the set, returns true. Set now contains [1,2]. randomSet.insert(2); // getRandom should return either 1 or 2 randomly. randomSet.getRandom(); // Removes 1 from the set, returns true. Set now contains [2]. randomSet.remove(1); // 2 was already in the set, so return false. randomSet.insert(2); // Since 2 is the only number in the set, getRandom always return 2. randomSet.getRandom();
解题思路:
因为要平均时间复杂度O(1),我们首先想到hashmap
我们可以用hashmap来存储值和下标的健值对,同时用一个数组来存储值
当我们需要插入时,可以首先通过hashmap判断是否存在,不存在再进行插入
当我们需要删除时,首先也需要判断值是否存在:
1. 若不存在返回false
2. 若存在:
a.首先将该元素与队尾元素交换(注意要更新队尾元素在hashmap中相应的下标)
b.从数组中弹出最后一个元素,从map中删除该元素。
代码:
class RandomizedSet { public: /** Initialize your data structure here. */ RandomizedSet() { } /** Inserts a value to the set. Returns true if the set did not already contain the specified element. */ bool insert(int val) { if(m.count(val)) return false; m[val] = nums.size(); nums.push_back(val); return true; } /** Removes a value from the set. Returns true if the set contained the specified element. */ bool remove(int val) { if(!m.count(val)) return false; int end = nums.back(); nums[m[val]] = end; m[end] = m[val]; nums.pop_back(); m.erase(val); return true; } /** Get a random element from the set. */ int getRandom() { return nums[rand() % nums.size()]; } private: vector<int> nums; unordered_map<int, int> m; }; /** * Your RandomizedSet object will be instantiated and called as such: * RandomizedSet obj = new RandomizedSet(); * bool param_1 = obj.insert(val); * bool param_2 = obj.remove(val); * int param_3 = obj.getRandom(); */