• python学习5—一些关于基本数据结构的练习题


    python学习5—一些关于基本数据结构的练习题

      1 # 1. use _ to connect entries in a list
      2 # if there are no numbers in list
      3 li = ['alex','eric','rain']
      4 v = '_'.join(li)
      5 print(v)
      6 # if there are numbers in list
      7 li = ['alex','eric',123]
      8 nli = []  # initialize a list new li (nli)
      9 for item in li:
     10     nli.append(str(item))  # add strred entries into list s
     11 v = "_".join(nli)
     12 print(nli,v)
     13 
     14 # 3. for a list
     15 li = ['alex','eric','rain']
     16 # realize the following functions:
     17 # a. figure out the length of tuple and output the result
     18 print(len(li))
     19 # b. add "seven" into the list
     20 li.append('seven')
     21 print(li)
     22 # c. insert "Tony" at the first place
     23 li.insert(0,'Tony')
     24 print(li)
     25 # d. insert "Kelly" at the second place
     26 li.insert(1,'Kelly')
     27 print(li)
     28 # e. delete "eric"
     29 li.remove('eric')
     30 print(li)
     31 ## f. delete the second entry, output the entry deleted
     32 #v = li.pop(1)
     33 #print(v,li)
     34 ## g. delete the third entry, output the list
     35 #li.pop(2)
     36 #print(li)
     37 ## h. delete the entries from 2 to 4, output the list
     38 #del li[1:4]
     39 #print(li)
     40 # i. reverse the list
     41 li.reverse()
     42 print(li)
     43 # j. use for, len, range to output the index of the list
     44 for i in range(len(li)):
     45     print(i)
     46 # k. use enumerate to output entries and index from 100
     47 for idx, elem in enumerate(li,100):
     48     print(idx,elem)
     49 # l. use for to output all the entries
     50 for item in li:
     51     print(item)
     52 
     53 # 4. 
     54 
     55 # 5. for a tuple 
     56 tu = ('alex','eric','rain')
     57 # realize the following functions:
     58 # a. figure out the length of tuple and output the result
     59 print(len(tu))
     60 # b. obtain the 2nd entry of the tuple and output it
     61 print(tu[1])
     62 # c. obtain the entries from 1 to 2 and output them
     63 print(tu[0:2])
     64 # d. use for to output all the entries of the tuple
     65 for item in tu:
     66     print(item)
     67 # e. use for, len, range to output the index of the tuple
     68 for i in range(0,len(tu)):
     69     print(i)
     70 # f. use enumrate output the entries and index of the tuple,
     71 # the index beginning at 10
     72 for idx, elem in enumerate(tu,10):
     73     print(idx,elem)
     74 
     75 # 6. for a tuple
     76 tu = ("alex",[11,22,{"k1":'v1',"k2":["age","name"],"k3":(11,22,33)},44])
     77 # add an entry in the value corresponding to "k2" if addable
     78 tu[1][2]["k2"].append("Seven")
     79 print(tu)
     80 
     81 # 10. output goods list, costoms input the number and show the good w.r.t the index
     82 li = ['iphone','laptop','cup','ship']
     83 idx = 1
     84 while idx > 0:
     85     good = input('please input the good added:')
     86     if bool(good):
     87         li.append(good) 
     88     idx = int(input('please input the number of the good:'))
     89     print(li[idx-1])
     90 
     91 # 12. False in bool: 3 + 3 + 1
     92 # {}, [], ()
     93 # 0, "", False
     94 # None
     95 
     96 # 13. there are two lists:
     97 l1 = [11,22,33]
     98 l2 = [22,33,44]
     99 # a. obtain the same entries of the two lists
    100 for i in l1:
    101     if i in l2:
    102         print(i)
    103 # b. obtain the entries in l1 not in l2
    104 for i in l1:
    105     if i not in l2:
    106         print(i)
    107 # c. obtain the entries in l2 not in l1
    108 for i in l2:
    109     if i not in l1:
    110         print(i)
    111 # d. obtain the entries that different in l1 and l2
    112 for i in l1:
    113     if i not in l2:
    114         print(i)
    115 for i in l2:
    116     if i not in l1:
    117         print(i)
    118 
    119 # 16. display contents in different pages, one page with 10 items
    120 user_list = []
    121 for i in range(1,302):
    122     temp = {'name':'alex'+str(i),'email':'alex@alex.com'+str(i)}
    123     user_list.append(temp)
    124 
    125 page = 1
    126 while page > 0 and page < 32:
    127     page = int(input('please input the page you want to look:'))
    128     start = (page - 1)*10
    129     end = page * 10
    130     result = user_list[start:end]
    131     for item in result:
    132         print(item)
    133 
    134 # 17. the numbers of combanions of two numbers in 1-8, and the two digits are different
    135 li = [1,2,3,4,5,6,7,8]
    136 count = 0
    137 l = len(li)
    138 for i in range(l):
    139     for j in range(l):
    140         if i != j:
    141             count += 1
    142 print(count)
    143 # 18. output 9*9 table
    144 for i in range(1,10):
    145     for j in range(i,10):
    146         print(i,'*',j,'=',i*j,end = '	')
    147     print('')
    148 
    149 # 19. for a list
    150 nums = [2,7,11,15,1,8,7]
    151 # find the pairs that the sum of which is 9
    152 l = len(nums)
    153 li = []
    154 for i in range(l):
    155     for j in range(i+1,l):
    156         if nums[i] + nums[j] == 9:
    157             li.append((nums[i],nums[j],))
    158 print(li)
    159 
    160 # 20. a costs 5 yuan, b costs 3 yuan, 3c costs 1 yuan
    161 #   use 100 yuan to buy 100 entities, give solutions
    162 for x in range(1,100//5):
    163     for y in range(1,100//3):
    164         for z in range(1,100):
    165             if x + y + z == 100 and 5*x + 3*y + z/3 == 100:
    166                 print(x,y,z)
    167 
    168 # end of file                
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  • 原文地址:https://www.cnblogs.com/yangjingxuan/p/11674536.html
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