• 背包问题


    将背包装满,要求时间复杂度最小 给定参数,背包容量S=100,N个物品,重量分别为1,55,2,44,3,5,3,56,7,3,5...
    <pre name="code" class="cpp">class Test
    {
    public:	
    	//将背包装满,要求时间复杂度最小 给定参数,背包容量S=100,N个物品,重量分别为1,55,2,44,3,5,3,56,7,3,5...
    	vector<int> ve;
    	void fill_bag(int S, int object_weight[], int len)
    	{		
    		//一参是数组,二参数组元素数量,三参每个元素的字节数,四参数是函数
    		qsort(object_weight,len,sizeof(int),compare);		
    		for(int i=len-1; i>=0; i--)
    		{
    			int c = S;
    			int j = i;
    			while(j>=0 && c>0)
    			{
    				j = bi_search(object_weight, j, c);
    				if(j==-1)
    					break;
    				ve.push_back(object_weight[j]);
    				if(object_weight[j]==c)
    				{
    					//ve.push_back(object_weight[j]);
    					for(int k=0; k<ve.size(); k++)
    						cout<<ve[k]<<" ";
    					return;
    				}				
    				c = c-object_weight[j];
    			}
    			ve.clear();
    		}
    		
    	}
    	
    };
    
    int compare(const void *a,const void *b)
    {
    	return *(int *)a-*(int *)b;
    }
    //二分查找离元素(可以等于)
    int bi_search(int num[10], int len, int target)
    {
    	int begin = 0;
    	int end = len-1;	
    	while(begin<end)
    	{
    		int mid = (begin+end)/2;		
    		//最近的一个
    		if(num[mid]==target)
    			return mid;
    		else if(num[mid]>target)
    			end = mid-1;
    		else
    			begin = mid+1;
    	}
    	cout<<"begin:"<<begin<<"end:"<<end<<endl;
    	if(begin==end && begin==0)
    		return -1;
    	return end;
    }
    void main1()
    {
    	int num[10]={11,35,65,25,79,54,34,66,92,30};
    	qsort(num,10,sizeof(int),compare);
    	for(int i=0;i<10;i++)
    		cout<<num[i]<<" ";
    	cout<<endl;
    	int index = bi_search(num, 10, 36);
    	cout<<index<<endl;
    }
    
    int main()
    {
    	//int num[10]={11,35,65,25,79,54,34,66,92,30};
    	int num[10]={11,25,30,34,35,54,65,66,79,92};
    	Test t;
    	t.fill_bag(100, num, 10);
    	return 0;
    }
    

    
    
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  • 原文地址:https://www.cnblogs.com/yan456jie/p/5369381.html
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