18.03.31 顺时针旋转90°24位真彩色bmp图片

#include <iostream>
#include <fstream>
#include <fstream>
#include <Windows.h>

using namespace std;

int main(int argc,char*argv[])
{
    tagBITMAPFILEHEADER a;//头信息块
    tagBITMAPINFOHEADER b;//描述块
    ifstream fin(argv[1], ios::binary | ios::in);//打开argv1用于读取，原文件
    if (!fin)cout << "Source file open error." << endl;
    ofstream fout(argv[2], ios::binary | ios::out | ios::trunc);
    if (!fout)cout << "New file open error. ";
    fin.read((char*)&a, sizeof(tagBITMAPFILEHEADER));
    fin.read((char*)&b, sizeof(tagBITMAPINFOHEADER));
    fout.write((char*)&a, sizeof(a));//写入头信息块
    int tmp;
    tmp = b.biWidth; b.biWidth = b.biHeight; b.biHeight = tmp;//交换宽高
    tmp = b.biXPelsPerMeter; b.biXPelsPerMeter = b.biYPelsPerMeter; b.biYPelsPerMeter = tmp;//交换xy分辨率
    fout.write((char*)&b, sizeof(b));//写入描述信息块
    int pixw = 3;//1像素3字节
    RGBTRIPLE *s = new RGBTRIPLE[b.biWidth*b.biHeight];
    int skip = (4 - ((b.biHeight*3) % 4)) % 4;
    for (LONG i = 0; i <b.biWidth; i++)
        {
            fin.read((char*)s + i*b.biHeight*3, b.biHeight*3);//转化成char 所以变成了*3……吧
            fin.seekg(skip, ios::cur);
        }
    int bu_n = (4 - (b.biWidth*pixw)%4) % 4;
    char *bu = new char[bu_n];
    for (int i = 0; i < bu_n; i++)
        bu[i] = 0;
    for (LONG i = b.biHeight - 1; i >= 0; i--) {
        for (LONG j = 0; j < b.biWidth; j++)
            fout.write((char*)&s[j*b.biHeight+i], sizeof(tagRGBTRIPLE));
            fout.write(bu, bu_n);
    }
    delete[]s;
    delete[]bu;
    fin.close();
    fout.close();
    return 0;
}

好像有点问题，虽然看上去好像成功了，但旋转后的图片会比原图多1kb

感觉1kb其实还挺多的，不知道是不是正常的

应该是因为0补全的原因……？

先存着……做错题导致我都不想做魔兽了tut