方法一:使用ViewData赋值
首先,我们创建一个User的实体类
- public class User
- {
- public string UserID;
- public string UserName;
- public string Sex;
- }
然后,我们在Action中添加假数据,并将假数据放到ViewData中
- public ActionResult test()
- {
- List<User> listUser = new List<User>();
- listUser.Add(new User
- {
- UserID = "001",
- UserName = "呵呵",
- Sex = "男"
- });
- listUser.Add(new User
- {
- UserID = "002",
- UserName = "哈哈",
- Sex = "女"
- }); listUser.Add(new User
- {
- UserID = "003",
- UserName = "嘿嘿",
- Sex = "男"
- });
- ViewData["listUser"] = listUser;
- return View();
- }
最后,我们在前台用ViewData给DataGrid赋值
- <div>
- <table id="dg" class="easyui-datagrid" style=" 600px; height: 300px" >
- <thead>
- <tr>
- <th data-options="field:'UserID',148,sortable:true">ID</th>
- <th data-options="field:'UserName',148,sortable:true">姓名</th>
- <th data-options="field:'Sex',148,sortable:true">性别</th>
- </tr>
- </thead>
- @foreach (ITOO.EvaluationUI.Models.User enUser in ViewData["listUser"] as List<ITOO.EvaluationUI.Models.User>)
- {
- <tr>
- <td>@enUser.UserID </td>
- <td>@enUser.UserName </td>
- <td>@enUser.Sex </td>
- </tr>
- }
- </table>
- </div>
方法二:使用url赋值
首先,我们在前台的DataGrid中加上URL属性
- <div>
- <table id="dg" class="easyui-datagrid" style=" 600px; height: 300px" >
- <thead>
- <tr>
- <th data-options="field:'UserID',148,sortable:true">ID</th>
- <th data-options="field:'UserName',148,sortable:true">姓名</th>
- <th data-options="field:'Sex',148,sortable:true">性别</th>
- </tr>
- </thead>
- </table>
- </div>
- <!--datagrid基本设置-->
- <script type="text/javascript">
- $(function () {
- $('#dg').datagrid({
- title: '测试表格',
- url: "/EvaluationSituation/jsonTest",
- pagination: true,//显示分页工具栏
- });
- });
- </script>
然后,我们在相应的控制器中添加一个得到json数据的方法
- public JsonResult jsonTest()
- {
- List<User> listUser = new List<User>();
- listUser.Add(new User {
- UserID ="001",
- UserName="呵呵",
- Sex ="男"
- });
- listUser.Add(new User
- {
- UserID = "002",
- UserName = "哈哈",
- Sex = "女"
- }); listUser.Add(new User
- {
- UserID = "003",
- UserName = "嘿嘿",
- Sex = "男"
- });
- JsonResult jsonUser = new JsonResult();
- jsonUser = Json(listUser);
- return jsonUser;
- }
上面介绍的两种方法能够解决我们给DataGrid赋值的问题,其中方法二里面除了将List集合转换成Json对象以外,我们还可以自己写一个方法将List转换成Json格式的字符串,这样也可以给DataGrid赋值。虽然我们能够赋值,但是这样做也有一些其他的问题,比如说怎么它的分页怎么实现,这就是下一节将要讲解的内容