Given a binary tree, count the number of nodes in each node’s left subtree, and store it in the numNodesLeft field.
Examples
1(6)
/
2(3) 3(0)
/
4(1) 5(0)
/
6(0) 7(0) 8(0)
The numNodesLeft is shown in parentheses.
/** * public class TreeNodeLeft { * public int key; * public TreeNodeLeft left; * public TreeNodeLeft right; * public int numNodesLeft; * public TreeNodeLeft(int key) { * this.key = key; * } * } */ public class Solution { public void numNodesLeft(TreeNodeLeft root) { // Write your solution here helper(root); } private int helper(TreeNodeLeft root) { if (root == null) { return 0; } int left = helper(root.left); int right = helper(root.right); root.numNodesLeft = left; return 1 + left + right; } }