• [LC] 146. LRU Cache


    Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and put.

    get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.
    put(key, value) - Set or insert the value if the key is not already present. When the cache reached its capacity, it should invalidate the least recently used item before inserting a new item.

    The cache is initialized with a positive capacity.

    Follow up:
    Could you do both operations in O(1) time complexity?

    Example:

    LRUCache cache = new LRUCache( 2 /* capacity */ );
    
    cache.put(1, 1);
    cache.put(2, 2);
    cache.get(1);       // returns 1
    cache.put(3, 3);    // evicts key 2
    cache.get(2);       // returns -1 (not found)
    cache.put(4, 4);    // evicts key 1
    cache.get(1);       // returns -1 (not found)
    cache.get(3);       // returns 3
    cache.get(4);       // returns 4
    
    class LRUCache {   
        private int capacity;
        private Map<Integer, Node> map;
        private Node head;
        private Node tail;
        // hash map makes O(1) to get and put
        // doubly LL makes removing easier
        public LRUCache(int capacity) {
            this.map = new HashMap<>();
            this.capacity = capacity;
            this.head = null;
            this.tail = null;
        }
        
        public int get(int key) {
            Node curNode = map.get(key);
            if (curNode == null) {
                return -1;
            }
    
            if (tail != curNode) {
                if (curNode == head) {
                    head = head.next;
                } else {                                 
                    curNode.prev.next = curNode.next;
                    curNode.next.prev = curNode.prev;
                }
                tail.next = curNode;
                curNode.prev = tail;
                tail = curNode;
            }
            return curNode.value;
        }
        
        public void put(int key, int value) {
            Node curNode = map.get(key);
            if (curNode != null) {
           // update the current Node, for get(), similiar with this snippet curNode.value
    = value; if (tail != curNode) { if (curNode == head) { head = head.next; } else { curNode.prev.next = curNode.next; curNode.next.prev = curNode.prev; } tail.next = curNode; curNode.prev = tail; tail = curNode; } } else { Node newNode = new Node(key, value); if (capacity == 0) { Node tmp = head; head = tmp.next; map.remove(tmp.key); capacity += 1; } if (head == null && tail == null) { head = newNode; } else { tail.next = newNode; newNode.prev = tail; } tail = newNode; capacity -= 1; map.put(key, newNode); } } } class Node { int key; int value; Node prev; Node next; public Node(int key, int value) { this.key = key; this.value = value; } } /** * Your LRUCache object will be instantiated and called as such: * LRUCache obj = new LRUCache(capacity); * int param_1 = obj.get(key); * obj.put(key,value); */
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  • 原文地址:https://www.cnblogs.com/xuanlu/p/12289705.html
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