• 动态规划~~矩阵链乘法


    基于自底向上的动态规划
    1
    #include <iostream> 2 #include <cstdio> 3 #include <algorithm> 4 #include <vector> 5 #include <cstring> 6 #include <string> 7 8 #define MAX 1000 9 using namespace std; 10 11 12 int a[MAX] = {0}, dp[MAX][MAX] = {0},path[MAX][MAX] = {0}, n; 13 14 void matrix_chain_order(){ 15 for(int r = 2; r <= n; r ++ ){ 16 for(int i = 1; i <= n-r; i ++){ 17 int j = i+r-1; 18 dp[i][j] =dp[i][i]+dp[i+1][j]+a[i]*a[i+1]*a[j+1]; 19 path[i][j] = i; 20 for(int k=i+1; k < j; k ++){ 21 if( dp[i][j] > dp[i][k] + dp[k+1][j] + a[i]*a[k+1]*a[j+1] ){ 22 dp[i][j] = dp[i][k] + dp[k+1][j] + a[i]*a[k+1]*a[j+1]; 23 path[i][j] = k; 24 } 25 } 26 } 27 } 28 } 29 30 void print_optimal_parens(int i, int j){ 31 if( i == j ) {cout<<'A'<<i;return;} 32 else{ 33 cout<<"("; 34 print_optimal_parens(i,path[i][j]); 35 print_optimal_parens(path[i][j]+1,j); 36 cout<<")"; 37 } 38 } 39 40 41 int main(){ 42 int T; 43 cin >> T; 44 while(T--){ 45 cin >> n ; 46 memset(a,0,sizeof(a)); 47 for(int i = 1; i <= n; i ++ ) cin >>a[i]; 48 memset(dp,0,sizeof(dp)); 49 memset(path,0,sizeof(path)); 50 matrix_chain_order(); 51 52 cout<<"("; 53 print_optimal_parens(1,n-1); 54 cout<<")"<<endl; 55 } 56 return 0; 57 }
     基于备忘录的自顶向下的动态规划
    1
    #include <iostream> 2 #include <cstdio> 3 #include <algorithm> 4 #include <vector> 5 #include <cstring> 6 #include <string> 7 8 #define MAX 1000 9 #define INF 1000000 10 using namespace std; 11 12 13 int a[MAX] = {0}, dp[MAX][MAX] = {0},path[MAX][MAX] = {0}, n; 14 15 int lookup_chain(int i,int j){ 16 if(dp[i][j] < INF) return dp[i][j]; 17 if(i == j ) return 0; 18 int u = lookup_chain(i,i)+lookup_chain(i+1,j) + a[i]*a[i+1]*a[j+1]; 19 path[i][j] = i; 20 for(int k = i+1; k < j; k ++ ){ 21 int t = lookup_chain(i,k)+lookup_chain(k+1,j)+a[i]*a[k+1]*a[j+1]; 22 if(t < u){ 23 u = t; 24 path[i][j] = k; 25 } 26 } 27 dp[i][j] = u; 28 return u; 29 } 30 31 void print_optimal_parens(int i, int j){ 32 if( i == j ) {cout<<'A'<<i;return;} 33 else{ 34 cout<<"("; 35 print_optimal_parens(i,path[i][j]); 36 print_optimal_parens(path[i][j]+1,j); 37 cout<<")"; 38 } 39 } 40 41 42 int main(){ 43 int T; 44 cin >> T; 45 while(T--){ 46 cin >> n ; 47 memset(a,0,sizeof(a)); 48 for(int i = 1; i <= n; i ++ ) cin >>a[i]; 49 memset(dp,INF,sizeof(dp)); 50 memset(path,0,sizeof(path)); 51 lookup_chain(1,n); 52 53 cout<<"("; 54 print_optimal_parens(1,n-1); 55 cout<<")"<<endl; 56 } 57 return 0; 58 }
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  • 原文地址:https://www.cnblogs.com/xiongqiangcs/p/3002888.html
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