查询表中相同数据的sql语句

--1、查找表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断
select * from people
where peopleId in (select   peopleId from   people group by   peopleId having count (peopleId) > 1)

--2、删除表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断，只留有rowid最小的记录
delete from people 
where peopleId in (select   peopleId from people group by   peopleId   having count (peopleId) > 1)
and rowid not in (select min(rowid) from   people group by peopleId having count(peopleId )>1)

--3、查找表中多余的重复记录（多个字段） 
select * from vitae a
where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having

count(*) > 1)

--4、删除表中多余的重复记录（多个字段），只留有rowid最小的记录
delete from vitae a
where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

--5、查找表中多余的重复记录（多个字段），不包含rowid最小的记录
select * from vitae a
where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having

count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

/**(二)
比方说
在A表中存在一个字段“name”，
而且不同记录之间的“name”值有可能会相同，
现在就是需要查询出在该表中的各记录之间，“name”值存在重复的项；**/
Select Name,Count(*) From A Group By Name Having Count(*) > 1
--如果还查性别也相同大则如下:
Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1

--(三)
--方法一
declare @max integer,@id integer
declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having

count(*) > 1
open cur_rows
fetch cur_rows into @id,@max
while @@fetch_status=0
begin
select @max = @max -1
set rowcount @max
delete from 表名 where 主字段 = @id
fetch cur_rows into @id,@max
end
close cur_rows
set rowcount 0

/**方法二

有两个意义上的重复记录，一是完全重复的记录，也即所有字段均重复的记录，

二是部分关键字段重复的记录，比如Name字段重复，而其他字段不一定重复或都重复可以忽略。**/

　　--1、对于第一种重复，比较容易解决，使用
select distinct * from tableName

　　--就可以得到无重复记录的结果集。

　　--如果该表需要删除重复的记录（重复记录保留1条），可以按以下方法删除
select distinct * into #Tmp from tableName
drop table tableName
select * into tableName from #Tmp
drop table #Tmp

　　--发生这种重复的原因是表设计不周产生的，增加唯一索引列即可解决。

　　--2、这类重复问题通常要求保留重复记录中的第一条记录，操作方法如下

　　--假设有重复的字段为Name,Address，要求得到这两个字段唯一的结果集
select identity(int,1,1) as autoID, * into #Tmp from tableName
select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID
select * from #Tmp where autoID in(select autoID from #tmp2)

　　--最后一个select即得到了Name，Address不重复的结果集（但多了一个autoID字段，实际写时可以写

--在select子句中省去此列）

--(四)查询重复
select * from tablename

where id in (select id from tablename group by id having count(id) > 1)