<一道题>abc+cba=1333,求满足条件的abc的值，隐含条件a!=0,c!=0

这类东西，无非就是穷举法。见下面代码：

#include <stdio.h>
#include <stdlib.h>

/*
*abc + cba = 1333 
*
*a = ?
*b = ?
*c = ?
*/



int main(int argc ,char **argv)
{
    int a=0;
    int b=0;
    int c=0;
    
    int index = 0;

    printf("abc + cba == 1333
");
    
    for(a = 1 ; a <= 9 ; a++)//a [1,9]
    {
        for(b = 0 ; b <= 9; b++)//b [0,9]
        {
            for(c = 1 ; c <= 9; c++)//c [1,9]
            {
                if(1333 == (100*a + 10*b + c + 100*c + 10*b + a))
                {
                    index++;
                    printf("I have found it !!! index : %d , a= %d, b= %d, c=%d
",index,a,b,c);//多谢1楼仁兄，找到了，却没有注意英文语法，已改found及I
                    
                }
            }
        }
    }

    printf("find over
");
    return 0;
}

运行结果;

tiger@ubuntu:/mnt/hgfs/e/Lessons/MyExercise/UtilLibs/EXERCISE$ ./abc
abc + cba == 1333
I have found it !!! index : 1 , a= 4, b= 1, c=9
I have found it !!! index : 2 , a= 5, b= 1, c=8
I have found it !!! index : 3 , a= 6, b= 1, c=7
I have found it !!! index : 4 , a= 7, b= 1, c=6
I have found it !!! index : 5 , a= 8, b= 1, c=5
I have found it !!! index : 6 , a= 9, b= 1, c=4
find over
tiger@ubuntu:/mnt/hgfs/e/Lessons/MyExercise/UtilLibs/EXERCISE$