/* * Given n non-negative integers a1, a2, ..., an , where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water. Note: You may not slant the container and n is at least 2. The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49. Example: Input: [1,8,6,2,5,4,8,3,7] Output: 49 来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/container-with-most-water 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 */ public class Lc11 { /* * (right-left) * min(rHeight,lHeight) 如果 min(rHeight,lheight)就向中间移动。/ * reght-left>1; */ public static int maxArea(int[] height) { int left = 0; int right = height.length - 1; int res = 0; while (right > left) { int width = right - left; int h = Math.min(height[left], height[right]); res = Math.max((width * h), res); if (height[left] > height[right]) { right--; } else { left++; } } return res; } public static void main(String[] args) { int[] height = { 1, 8, 6, 2, 5, 4, 8, 3, 7 }; System.out.println(maxArea(height)); } }