题目链接
https://leetcode.com/problems/binary-tree-preorder-traversal/description/
题目描述
Given a binary tree, return the preorder traversal of its nodes' values.
Example:
Input: [1,null,2,3]
1
2
/
3
Output: [1,2,3]
Follow up: Recursive solution is trivial, could you do it iteratively?
题解
使用一个栈来保存数据,把每一个节点的子节点依次入栈,先右节点,再左节点。
代码
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public List<Integer> preorderTraversal(TreeNode root) {
List<Integer> list = new LinkedList<>();
if (root == null) { return list; }
Stack<TreeNode> s = new Stack<>();
s.push(root);
while (!s.isEmpty()) {
TreeNode node = s.pop();
list.add(node.val);
if (node.right != null) { s.push(node.right); }
if (node.left != null) { s.push(node.left); }
}
return list;
}
}