密码学笔记——培根密码

培根密码，培根所用的密码是一种本质上用二进制数设计的，没有用通常的0和1来表示，而是采用a和b

一、培根密码加密方式

    第一种方式：
    A aaaaa B aaaab C aaaba D aaabb E aabaa F aabab G aabba H aabbb I abaaa J abaab
    K ababa L ababb M abbaa N abbab O abbba P abbbb Q baaaa R baaab S baaba T baabb
    U babaa V babab W babba X babbb Y bbaaa Z bbaab

    第二种方式
    a AAAAA   g AABBA    n ABBAA   t BAABA
    b AAAAB   h AABBB    o ABBAB   u-v BAABB
    c AAABA   i-j ABAAA  p ABBBA   w BABAA
    d AAABB   k ABAAB    q ABBBB   x BABAB
    e AABAA   l ABABA    r BAAAA   y BABBA
    f AABAB   m ABABB    s BAAAB   z BABBB

二、举例

    例1、 baabaaabbbabaaabbaaaaaaaaabbabaaaabaaaaaabaaabaabaaaabaabbbaabbbaababb

             baaba aabbb abaaa bbaaa aaaaa abbab aaaab aaaaa abaaa baaba  aaaba abbba abbba ababb

                s           h         i           y         a         n         b         a        i           s          c         o          o        l 

           

  

    例2、明文是LOVE，用“随意选取句子和文”加密，得到密文就是“SuLyi XuanQ uJuZi HEwEN”（这里用大写字母代表a,小写字母代表b）

              SuLyi  XuanQ uJuZi HEwEN

              ababbabbbabababaabaa

            

        这里，加密者使用两种不同字体，准备好一篇包含相同ab字数的假信息后，即两种字体分别代表a型和b型。然后假信息中的每个字母按字体来决定其代表“a”还是“b”。

    例3、明文:now is a good t.........密码术 密码学 密码论坛 密码术论坛, `, Q" J/ K2 F9 S
                      n       o        w        i        s       a        g       o        o        d        t
                  abbaa abbab babaa abaaa baaab aaaaa aabba abbab abbab aaabb baaba
        密文:BOWED ASTER PINED JOKED THEIR BLACK HASTE ARRAY INSET CHEST SLING

        加密规则：（1）a-m -> a ，也就是说 a ——m 的所有字母都能替换成 a。

                                   n-z  -> b ，也就是说 n ——z 的所有字母都能替换成 b。

                          （2）a-m <- a ，也就是说 a 可以替换 a——m 中的任何一个字母。

                                   n-z  <- a ，也就是说 b 可以替换 n——z  中的任何一个字母。

       Ps:密文中的单词都是根据加密规则随便拼凑出来的，为了使加密更隐蔽，一般拼凑出来的单词可连成通顺的一句话

三、附加解密Python脚本如下：

#!/usr/bin/python
# -*- coding: utf-8 -*-
import re

alphabet = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']

first_cipher = ["aaaaa","aaaab","aaaba","aaabb","aabaa","aabab","aabba","aabbb","abaaa","abaab","ababa","ababb","abbaa","abbab","abbba","abbbb","baaaa","baaab","baaba","baabb","babaa","babab","babba","babbb","bbaaa","bbaab"]

second_cipher = ["aaaaa","aaaab","aaaba","aaabb","aabaa","aabab","aabba","aabbb","abaaa","abaaa","abaab","ababa","ababb","abbaa","abbab","abbba","abbbb","baaaa","baaab","baaba","baabb","baabb","babaa","babab","babba","babbb"]

def encode():
    string = raw_input("please input string to encode:
")
    e_string1 = ""
    e_string2 = ""
    for index in string:
        for i in range(0,26):
            if index == alphabet[i]:
                e_string1 += first_cipher[i]
                e_string2 += second_cipher[i]
                break
    print "first encode method result is:
"+e_string1
    print "second encode method result is:
"+e_string2
    return


def decode():
    e_string = raw_input("please input string to decode:
")
    e_array = re.findall(".{5}",e_string)
    d_string1 = ""
    d_string2 = ""
    for index in e_array:
        for i in range(0,26):
            if index == first_cipher[i]:
                d_string1 += alphabet[i]
            if index == second_cipher[i]:
                d_string2 += alphabet[i]
    print "first decode method result is:
"+d_string1
    print "second decode method result is:
"+d_string2
    return


if __name__ == '__main__':
    while True:
        print "	*******Bacon Encode_Decode System*******"
        print "input should be lowercase,cipher just include a b"
        print "1.encode
2.decode
3.exit"
        s_number = raw_input("please input number to choose
")
        if s_number == "1":
            encode()
            raw_input()
        elif s_number == "2":
            decode()
            raw_input()
        elif s_number == "3":
            break
        else:
            continue

             注：本笔记参考文献百度百科、xuqi7博客、 曜希JFSH

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              ps:萌新一枚，本文纯为学习笔记，以防某日犯傻忘记--。如有不妥处，望大佬们赐教~