• 10.1jihe


    两种操作,1是加入数字,二是找最接近的
    用set或者平衡二叉树就好了
    只写了二叉树的,套版子就好

    #include<bits/stdc++.h>
    #define sf scanf
    #define scf(x) scanf("%d",&x)
    #define scff(x,y) scanf("%d%d",&x,&y)
    #define scfff(x,y,z) scanf("%d%d%d",&x,&y,&z)
    #define pf printf
    #define prf(x) printf("%d
    ",x)
    #define mm(x,b) memset((x),(b),sizeof(x))
    #define rep(i,a,n) for (int i=a;i<n;i++)
    #define per(i,a,n) for (int i=a;i>=n;i--)
    typedef long long ll;
    const ll mod=1e9+100;
    const double eps=1e-8;
    using namespace std;
    const double pi=acos(-1.0);
    const int inf=0xfffffff;
    const int N=1e5+7;
    struct node
    {
    	int lc,rc,h,v;
    }tree[N];
    int pos=0,x1,x2,x3,root;
    int right_rotate(int r)//zig右旋
    {
    	int t = tree[r].lc;
    	tree[r].lc = tree[t].rc;
    	tree[t].rc = r;
    	tree[r].h = max(tree[tree[r].lc].h,tree[tree[r].rc].h)+1;
    	tree[t].h = max(tree[tree[t].lc].h,tree[tree[t].rc].h)+1;
    	return t;
    }
    int left_rotate(int r)//zag左旋
    {
    	int t = tree[r].rc;
    	tree[r].rc = tree[t].lc;
    	tree[t].lc = r;
    	tree[r].h = max(tree[tree[r].lc].h,tree[tree[r].rc].h)+1;
    	tree[t].h = max(tree[tree[t].lc].h,tree[tree[t].rc].h)+1;
    	return t;
    }
    int right_left_rotate(int r)//zigzag双旋
    {
    	tree[r].rc = right_rotate(tree[r].rc);
    	return left_rotate(r);
    }
    int left_right_rotate(int r)//zagzig双旋
    {
    	tree[r].lc = left_rotate(tree[r].lc);
    	return right_rotate(r);
    }
    void maintain(int &r)
    {
    	if(tree[tree[r].lc].h == tree[tree[r].rc].h+2)//左子树高了
    	{
    		int t = tree[r].lc;
    		if(tree[tree[t].lc].h == tree[tree[r].rc].h+1) r = right_rotate(r);//左子树的左儿子,对应第一种情况
    		else if(tree[tree[t].rc].h == tree[tree[r].rc].h+1) r = left_right_rotate(r);	
    	}
    	else if(tree[tree[r].rc].h == tree[tree[r].lc].h+2)//右子树高了
    	{
    		int t = tree[r].rc;
    		if(tree[tree[t].rc].h == tree[tree[r].lc].h+1) r = left_rotate(r);//右子树的右儿子,对应第四种情况
    		else if(tree[tree[t].lc].h == tree[tree[r].lc].h+1) r = right_left_rotate(r);
    	}
    	tree[r].h = max(tree[tree[r].lc].h,tree[tree[r].rc].h)+1;//高度更新
    }
    void prem(int x,int r)//找x的前驱
    {
        if(r == 0) return;
        if(tree[r].v < x)
        {
            x1 = tree[r].v;
            prem(x,tree[r].rc);
        }
        else prem(x,tree[r].lc);
    }
    void nexm(int x,int r)//找x后一个数字
    {
        if(r == 0) return;
        if(tree[r].v > x)
        {
            x2 = tree[r].v;
            nexm(x,tree[r].lc);
        }
        else nexm(x,tree[r].rc);
    }
    void find(int x,int r)//找到x
    {
    	if(r==0) return;
    	if(tree[r].v ==x)
    	{
    		x3=x;
    		return ;
    	}
    	if(tree[r].v > x)
            find(x,tree[r].lc);
        else 
    		find(x,tree[r].rc);
    }
    int insert(int r,int x)
    {
    	if(r == 0)//找到一个空的节点,赋值
    	{
    		tree[++pos].h = 1;//高度初始化
    		tree[pos].v = x;
    		return pos;
    	}
    	if(x < tree[r].v) tree[r].lc = insert(tree[r].lc,x);//插入的数小于根节点,因此在它的左子树插入
    	else if(x > tree[r].v) tree[r].rc = insert(tree[r].rc,x);
    	maintain(r);//维持节点r的平衡
    	return r;//返回新的根节点
    }
    int main()
    {
    	int n,aa,x;scf(n);
    	while(n--)
    	{
    		scff(aa,x);
    		if(aa==1)
    			root=insert(root,x);	
    		else
    		{
    				x1=x2=x3=0;
    				prem(x,root);
    				nexm(x,root);
    				find(x,root);
    			//	cout<<x1<<" "<<x2<<endl;
    				if(x3)
    					prf(x3);
    				else if(x1==0&&x2==0)
    					pf("Empty!
    ");
    				else if(x1==0)
    					prf(x2);
    				else if(x2==0)
    					prf(x1);
    				else
    				{
    					if(x-x1==x2-x)
    						pf("%d %d
    ",x1,x2);
    					else
    					{
    						if(x-x1<x2-x)
    							prf(x1);
    						else
    							prf(x2);
    					}
    				}
    		}
    	}
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/wzl19981116/p/10087369.html
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