• Multiply Strings


    题目:

    Given two numbers represented as strings, return multiplication of the numbers as a string.

    Note: The numbers can be arbitrarily large and are non-negative.

     

    class Solution {
    public:
        string addTwoString(string nums1, string nums2) {
    
            int n1 = nums1.size();
            int n2 = nums2.size();
    
            if (n1 < n2)
                return addTwoString(nums2, nums1);
    
            int minlen = n2;
            int maxlen = n1;
            string result;
            int carry = 0;
            for (int i = 0; i < minlen; i++) {
                int sum = nums1[--n1] - '0' + nums2[--n2] - '0' + carry;
                carry = sum / 10;
                int a = sum % 10;
                result.push_back(a + '0');
            }
            for (int i = minlen; i < maxlen; i++) {
                int sum = nums1[--n1] - '0' + carry;
                carry = sum / 10;
                int a = sum % 10;
                result.push_back(a + '0');
            }
    
            if (carry != 0)
                result.push_back(carry + '0');
            reverse(result.begin(), result.end());
    
            return result;
        }
    
        string multiply(string nums1, string nums2) {
            string result = "0";
            if(nums1 == "0" || nums2 == "0") return result;
            vector<string> tmpResult;
            int n1 = nums1.size();
            int n2 = nums2.size();
    
            int carry = 0;
            reverse(nums1.begin(),nums1.end());
            reverse(nums2.begin(),nums2.end());
    
            for (int i = 0; i < n1; i++) {
                string str;
                for (int j = 0; j < n2; j++) {
                    int sum = (nums1[i] - '0') * (nums2[j] - '0') + carry;
                    carry = sum / 10;
                    int a = sum - carry * 10;
                    str.push_back(a + '0');
                }
                if (carry != 0)
                    str.push_back(carry+'0');
                carry = 0;
                reverse(str.begin(), str.end());
                for (int k = 0; k < i; k++) {
                    str.push_back('0');
                }
                tmpResult.push_back(str);
            }
    
            int size = tmpResult.size();
    
            for (int i = 0; i < size; i++) {
                result = addTwoString(result, tmpResult[i]);
            }
            return result;
        }
    };

     

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  • 原文地址:https://www.cnblogs.com/wxquare/p/5216465.html
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