参考自:http://blog.csdn.net/niushuai666/article/details/6973134
/* 遇到素数需要打表时,先估算素数的个数: num = n / lnx; num为大概数字,越大误差越小(只是估计,用于估算素数表数组大小) 这个打表法效率貌似很高,网上说几乎达到了线性时间(不知道是真是假=。=) */ #include<iostream> #include<cstring> #include<cstdio> #include<ctime> #include<algorithm> using namespace std; const int MAXSIZE = 10100000; int n; bool visit[MAXSIZE]; int prime[MAXSIZE]; void init_prim(){ memset(visit, true, sizeof(visit)); int num = 0; for (int i = 2; i <= n; ++i){ if (visit[i] == true){ num++; prime[num] = i; } for (int j = 1; ((j <= num) && (i * prime[j] <= n)); ++j){ visit[i * prime[j]] = false; if (i % prime[j] == 0) break; //点睛之笔 } } } int main(){ memset(prime, 0, sizeof(prime)); int count = 0; cin>>n; init_prim(); for(int i = 0; i <= n; ++i) if(prime[i]){ cout<<prime[i]<<" "; count++; } cout<<endl; cout<<"素数个数为:"<<count<<endl; }