思路:这个博客写的不错:http://www.cnblogs.com/windysai/p/4058235.html
代码:
#include<bits/stdc++.h> using namespace std; #define ll long long #define pb push_back #define mem(a,b) memset((a),(b),sizeof(a)) const ll INF=1e18; ll c1,c2,x,y; bool check(ll v) { ll f1=v/x;//整除x ll f2=v/y;///整除y ll b=v/(x*y);//都整除 ll _f1=f1-b;//只整除x ll _f2=f2-b;//只整除y ll o=v-_f1-_f2-b;//都不整除 ll t1=c1-_f2;//还需要的个数 if(t1<=0)t1=0; ll t2=c2-_f1;//还需要的个数 if(t2<=0)t2=0; return (t1+t2<=o); } int main() { cin>>c1>>c2>>x>>y; ll l=1,r=INF,m; while(l<r) { m=(l+r)>>1; if(check(m))r=m; else l=m+1; } m=(l+r)>>1; cout<<m<<endl; return 0; }