Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1
100
Sample Output
1
5050
巨坑无比
我直接用等差公式 WA到根本停不下来
题目中标红的字是关键
n*(n+1)可能会超出32位
所以先 n/2(n%2==0)
或者(n+1)/2 ---(n%2==1)
代码自己写吧