• 子集和排列


    1 Subsets

        public List<List<Integer>> subsets(int[] nums) {
            List<List<Integer>> result = new ArrayList<>();
            if (nums.length == 0) {
                return result;
            }
            ArrayList<Integer> list = new ArrayList<>();
            subsetsHelper(nums, 0, list, result);
            return result;
        }
        void subsetsHelper(int[] nums, int pos, List<Integer> list, List<List<Integer>> result){
            result.add(new ArrayList<>(list));
            for (int i = pos; i < nums.length; i++) {
                list.add(nums[i]);
                subsetsHelper(nums, i + 1, list, result);
                list.remove(list.size() - 1);
            }
        }
    View Code

     2 Subsets II

        public List<List<Integer>> subsetsWithDup(int[] nums) {
            List<List<Integer>> result = new ArrayList<>();
            if (nums.length == 0) {
                return result;
            }
            Arrays.sort(nums);
            ArrayList<Integer> list = new ArrayList<>();
            subsetsHelper(nums, 0, list, result);
            return result;
        }
        void subsetsHelper(int[] nums, int pos, List<Integer> list, List<List<Integer>> result){
            result.add(new ArrayList<>(list));
            for (int i = pos; i < nums.length; i++) {
                if (i > pos && nums[i] == nums[i - 1]){
                    continue;
                }
                list.add(nums[i]);
                subsetsHelper(nums, i + 1, list, result);
                list.remove(list.size() - 1);
            }
        }
    View Code

    3 Permutations

        public List<List<Integer>> permute(int[] nums) {
            // write your code here
            List<List<Integer>> res = new ArrayList<>();
            if (nums == null || nums.length == 0) {
                res.add(new ArrayList<Integer>());
                return res;
            }
            List<Integer> list = new ArrayList<>();
            helper(nums, list, res);
            return res;
        }
        
        void helper(int[] nums, List<Integer> list, List<List<Integer>> res) {
            if (list.size() == nums.length) {
                res.add(new ArrayList<>(list));
                return;
            }
            for (int i = 0; i < nums.length; i++) {
                if (list.contains(nums[i])) {
                    continue;
                }
                list.add(nums[i]);
                helper(nums, list, res);
                list.remove(list.size() - 1);
            }
        }
    View Code

    4 Permutations II

        public List<List<Integer>> permuteUnique(int[] nums) {
            // Write your code here
            List<List<Integer>> result = new ArrayList<>();
            if (nums == null || nums.length == 0) {
                result.add(new ArrayList<Integer>());
                return result;
            }
            Arrays.sort(nums);
            List<Integer> list = new ArrayList<>();
            boolean[] used = new boolean[nums.length];
            helper(nums, list, used, result);
            return result;
        }
        void helper(int[] nums, List<Integer> list, boolean[] used, List<List<Integer>> result) {
            if (list.size() == nums.length) {
                result.add(new ArrayList<>(list));
                return;
            }
            for (int i = 0; i < nums.length; i++) {
                if (used[i] || (i > 0 && nums[i] == nums[i - 1] && !used[i - 1])) {
                    continue;
                }
                used[i] = true;
                list.add(nums[i]);
                helper(nums, list, used, result);
                used[i] = false;
                list.remove(list.size() - 1);
            }
        }
    View Code

    5 Combination Sum    可以有重复

        public ArrayList<ArrayList<Integer>> combinationSum(int[] candidates, int target) 
        {
            ArrayList<ArrayList<Integer>> res = new ArrayList<ArrayList<Integer>>();
            if (candidates == null || candidates.length == 0)
            {
                return res;
            }
            Arrays.sort(candidates);
            helper(candidates, 0, target, new ArrayList<Integer>(), res);
            return res;
        }
        private void helper(int[] candidates, int start, int target, ArrayList<Integer> item,
                ArrayList<ArrayList<Integer>> res) {
            // TODO Auto-generated method stub
            if (target < 0)
            {
                return;
            }
            if (target == 0)
            {
                res.add(new ArrayList<>(item));
                return;
            }
            for (int i = start; i < candidates.length; i++)
            {
                if (i > 0 && candidates[i] == candidates[i - 1])
                {
                    continue;
                }
                item.add(candidates[i]);
                helper(candidates, i, target - candidates[i], item, res);
                item.remove(item.size() - 1);
            }
        }
    View Cod

    6 Combination Sum     不可以有重复

    public List<List<Integer>> combinationSum2(int[] nums, int target) {
        List<List<Integer>> list = new ArrayList<>();
        Arrays.sort(nums);
        backtrack(list, new ArrayList<>(), nums, target, 0);
        return list;
        
    }
    
    private void backtrack(List<List<Integer>> list, List<Integer> tempList, int [] nums, int remain, int start){
        if(remain < 0) return;
        else if(remain == 0) list.add(new ArrayList<>(tempList));
        else{
            for(int i = start; i < nums.length; i++){
                if(i > start && nums[i] == nums[i-1]) continue; // skip duplicates
                tempList.add(nums[i]);
                backtrack(list, tempList, nums, remain - nums[i], i + 1);
                tempList.remove(tempList.size() - 1); 
            }
        }
    } 
    View Code

    7 Palindrome Partitioning

    public class Solution {
        public List<List<String>> partition(String s) {
            List<List<String>> res = new ArrayList<>();
            if (s.length() == 0) return res;
            dfs(s, 0, new ArrayList<String>(), res);
            return res;
        }
        public void dfs(String s, int index, ArrayList<String> item, List<List<String>> res){
            if (s.length() == index) {
                res.add(new ArrayList<>(item));
                return;
            }
            for (int i = index; i < s.length(); i++){
                if (isP(s, index, i)){
                    item.add(s.substring(index, i + 1));
                    dfs(s, i + 1, item, res);
                    item.remove(item.size() - 1);
                }
            }
        }
        public boolean isP(String s, int l, int r){
            while (l < r) {
                if (s.charAt(l) != s.charAt(r)){
                    return false;
                }
                l++;r--;
            }
            return true;
        }
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/whesuanfa/p/7435894.html
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