In MATLAB, there is a very useful function called 'reshape', which can reshape a matrix into a new one with different size but keep its original data.
You're given a matrix represented by a two-dimensional array, and two positive integers r and c representing the row number and column number of the wanted reshaped matrix, respectively.
The reshaped matrix need to be filled with all the elements of the original matrix in the same row-traversing order as they were.
If the 'reshape' operation with given parameters is possible and legal, output the new reshaped matrix; Otherwise, output the original matrix.
把矩阵reshape成r行c列的。如果原本的n*m不等于r*c的话就返回原矩阵
class Solution(object): def matrixReshape(self, nums, r, c): """ :type nums: List[List[int]] :type r: int :type c: int :rtype: List[List[int]] """ n = len(nums) m = len(nums[0]) if n * m != r * c: return nums row = 0 col = 0 ans = [] for i in range(r): ans.append([0] * c) for i in range(n): for j in range(m): ans[row][col] = nums[i][j] col += 1 if col == c: col = 0 row += 1 return ans