• POJ 2419 Forests(模拟)


    题目链接:

    https://cn.vjudge.net/problem/POJ-2419

    题目描述:

    If a tree falls in the forest, and there's nobody there to hear, does it make a sound? This classic conundrum was coined by George Berkeley (1685-1753), the Bishop and influential Irish philosopher whose primary philosophical achievement is the advancement of what has come to be called subjective idealism. He wrote a number of works, of which the most widely-read are Treatise Concerning the Principles of Human Knowledge (1710) and Three Dialogues between Hylas and Philonous (1713) (Philonous, the "lover of the mind," representing Berkeley himself).
    Input
    A forest contains T trees numbered from 1 to T and P people numbered from 1 to P. Standard input consists of a line containing P and T followed by several lines, containing a pair of integers i and j, indicating that person i has heard tree j fall.
    Output
    People may have different opinions as to which trees, according to Berkeley, have made a sound. Output how many different opinions are represented in the input? Two people hold the same opinion only if they hear exactly the same set of trees. You may assume that P < 100 and T < 100.
    Sample Input
    3 4
    1 2
    3 3
    1 3
    2 2
    3 2
    2 4
    
    Sample Output
    2
    
     1 /*
     2 题意描述 
     3 有p个人去听t棵树倒下的声音,问有几种不同的观点数
     4 
     5 解题思路
     6 用二维数组记录i听到j倒下,如果某个人听到的结果和另一个完全相同,说明这两个人是一种观点,需要总观点数减一 
     7 */ 
     8 #include<cstdio>
     9 #include<cstring>
    10 const int maxn=100+10;
    11 
    12 bool g[maxn][maxn];
    13 int t,p;
    14 int common(int a,int b);
    15 
    16 int main()
    17 {
    18     int x,y;
    19     memset(g,0,sizeof(bool)*maxn*maxn);
    20     scanf("%d%d",&p,&t);
    21     while(scanf("%d%d",&x,&y) != EOF){
    22         g[x][y]=1;
    23     }
    24     int sum=p;
    25     for(int i=1;i<=p-1;i++){
    26         for(int j=i+1;j<=p;j++){
    27             if(common(i,j)){
    28                 sum--;
    29                 break;//遇到一个重复以后,总观点数减1后直接判断下一个 
    30             }    
    31         }
    32     }
    33     printf("%d
    ",sum);
    34     return 0;
    35 } 
    36 
    37 int common(int a,int b)
    38 {
    39     for(int i=1;i<=t;i++){
    40         if(g[a][i] != g[b][i])
    41             return 0;
    42     }
    43     return 1;
    44 }
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  • 原文地址:https://www.cnblogs.com/wenzhixin/p/9338101.html
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