• 622. Design Circular Queue


    Design your implementation of the circular queue. The circular queue is a linear data structure in which the operations are performed based on FIFO (First In First Out) principle and the last position is connected back to the first position to make a circle. It is also called "Ring Buffer".

    One of the benefits of the circular queue is that we can make use of the spaces in front of the queue. In a normal queue, once the queue becomes full, we cannot insert the next element even if there is a space in front of the queue. But using the circular queue, we can use the space to store new values.

    Your implementation should support following operations:

    • MyCircularQueue(k): Constructor, set the size of the queue to be k.
    • Front: Get the front item from the queue. If the queue is empty, return -1.
    • Rear: Get the last item from the queue. If the queue is empty, return -1.
    • enQueue(value): Insert an element into the circular queue. Return true if the operation is successful.
    • deQueue(): Delete an element from the circular queue. Return true if the operation is successful.
    • isEmpty(): Checks whether the circular queue is empty or not.
    • isFull(): Checks whether the circular queue is full or not.

    Example:

    MyCircularQueue circularQueue = new MyCircularQueue(3); // set the size to be 3
    circularQueue.enQueue(1);  // return true
    circularQueue.enQueue(2);  // return true
    circularQueue.enQueue(3);  // return true
    circularQueue.enQueue(4);  // return false, the queue is full
    circularQueue.Rear();  // return 3
    circularQueue.isFull();  // return true
    circularQueue.deQueue();  // return true
    circularQueue.enQueue(4);  // return true
    circularQueue.Rear();  // return 4
    

    Note:

    • All values will be in the range of [0, 1000].
    • The number of operations will be in the range of [1, 1000].
    • Please do not use the built-in Queue library.
    class MyCircularQueue {
    
        final int[] arr;
        int front = 0, len = 0, rear = -1;
        /** Initialize your data structure here. Set the size of the queue to be k. */
        public MyCircularQueue(int k) {
            arr = new int[k];
        }
        
        /** Insert an element into the circular queue. Return true if the operation is successful. */
        public boolean enQueue(int value) {
            if(isFull()) return false;
            else{
                rear = (1 + rear) % arr.length;
                arr[rear] = value;
                len++;
            }
            return true;
        }
        
        /** Delete an element from the circular queue. Return true if the operation is successful. */
        public boolean deQueue() {
            if(isEmpty()) return false;
            else{
                front = (1 + front) % arr.length;
                len--;
            }
            return true;
        }
        
        /** Get the front item from the queue. */
        public int Front() {
            return isEmpty() ? -1 : arr[front];
        }
        
        /** Get the last item from the queue. */
        public int Rear() {
            return isEmpty() ? -1 : arr[rear];
        }
        
        /** Checks whether the circular queue is empty or not. */
        public boolean isEmpty() {
            return len == 0;
        }
        
        /** Checks whether the circular queue is full or not. */
        public boolean isFull() {
            return len == arr.length;
        }
    }
    
    /**
     * Your MyCircularQueue object will be instantiated and called as such:
     * MyCircularQueue obj = new MyCircularQueue(k);
     * boolean param_1 = obj.enQueue(value);
     * boolean param_2 = obj.deQueue();
     * int param_3 = obj.Front();
     * int param_4 = obj.Rear();
     * boolean param_5 = obj.isEmpty();
     * boolean param_6 = obj.isFull();
     */

     像设置两个指针一样,front和end,用mod来实现circular,用数组实现调取和存入,len是当前queue的size。

    每次入队列不会影响front,只改变往后挪一位rear

    同样每次出队列不会影响rear,也往后挪一位front,如果超了数组长度就通过mod重来

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  • 原文地址:https://www.cnblogs.com/wentiliangkaihua/p/13217132.html
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