Given the array of integers nums
, you will choose two different indices i
and j
of that array. Return the maximum value of (nums[i]-1)*(nums[j]-1)
.
Example 1:
Input: nums = [3,4,5,2] Output: 12 Explanation: If you choose the indices i=1 and j=2 (indexed from 0), you will get the maximum value, that is, (nums[1]-1)*(nums[2]-1) = (4-1)*(5-1) = 3*4 = 12.
Example 2:
Input: nums = [1,5,4,5] Output: 16 Explanation: Choosing the indices i=1 and j=3 (indexed from 0), you will get the maximum value of (5-1)*(5-1) = 16.
Example 3:
Input: nums = [3,7] Output: 12
Constraints:
2 <= nums.length <= 500
1 <= nums[i] <= 10^3
class Solution { public int maxProduct(int[] nums) { int le = nums.length; Arrays.sort(nums); return (nums[le-1]-1)*(nums[le-2]-1); } }
找最大的两个数的乘积