• 350. Intersection of Two Arrays II


    Given two arrays, write a function to compute their intersection.

    Example 1:

    Input: nums1 = [1,2,2,1], nums2 = [2,2]
    Output: [2,2]
    

    Example 2:

    Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4]
    Output: [4,9]

    Note:

    • Each element in the result should appear as many times as it shows in both arrays.
    • The result can be in any order.

    Follow up:

    • What if the given array is already sorted? How would you optimize your algorithm?
    • What if nums1's size is small compared to nums2's size? Which algorithm is better?
    • What if elements of nums2 are stored on disk, and the memory is limited such that you cannot load all elements into the memory at once?
    class Solution {
      public int[] intersect(int[] nums1, int[] nums2) {
        Arrays.sort(nums1);
        Arrays.sort(nums2);
        ArrayList result = new ArrayList();
        for (int i = 0, j = 0; i < nums1.length && j < nums2.length; ){
            if (nums1[i] == nums2[j]){
                result.add(nums1[i]);
                i++;
                j++;
            } else if (nums1[i] < nums2[j]) {
                i++;
            } else {
                j++;
            }
        }
        int[] res = new int[result.size()];
        for (int i = 0; i < result.size(); i++){
            res[i] = (int) result.get(i);
        }
        return res;
        }
    }
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  • 原文地址:https://www.cnblogs.com/wentiliangkaihua/p/11770482.html
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