ACM-ICPC 2018 沈阳赛区网络预赛

Supreme Number

• 
  
• 1000ms
• 131072K

 

A prime number (or a prime) is a natural number greater than 111 that cannot be formed by multiplying two smaller natural numbers.

Now lets define a number NNN as the supreme number if and only if each number made up of an non-empty subsequence of all the numeric digits of NNN must be either a prime number or 111.

For example, 171717 is a supreme number because 111, 777, 171717 are all prime numbers or 111, and 191919 is not, because 999 is not a prime number.

Now you are given an integer N (2≤N≤10100)N (2 leq N leq 10^{100})N (2≤N≤10100), could you find the maximal supreme number that does not exceed NNN?

Input

In the first line, there is an integer T (T≤100000)T (T leq 100000)T (T≤100000) indicating the numbers of test cases.

In the following TTT lines, there is an integer N (2≤N≤10100)N (2 leq N leq 10^{100})N (2≤N≤10100).

Output

For each test case print "Case #x: y", in which xxx is the order number of the test case and yyy is the answer.

样例输入

2
6
100

样例输出

Case #1: 5
Case #2: 73

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int a[20] = {1,2,3,5,7,11,13,17,23,31,37,53,71,73,113,131,137,173,311,317
                };
    int s;
    int t,count = 1;
    cin >> t;
    while(t--)
    {
        cin >> s;
        cout << "Case #" << count++ << ": " ;
        if(s >= 317)
        {
            cout << a[19] << endl;
            continue;
        }
        else
        {
            for(int i = 19; i >= 0; i --)
            {
                if(s >= a[i])
                {
                    cout << a[i] << endl;
                    break;
                }
            }
        }
    }
    return 0;
}