1. Concat() – 串联序列(有重复项)
var healthFoods = new List<string> { "fruits", "vegetables", "grains", "proteins" };
var myFoods = new List<string> { "grains", "proteins", "M&Ms", "soda" };
var healthyFirst = healthFoods.Concat(myFoods); // 返回序列: fruits, vegetables, grains, proteins, grains, proteins, M&Ms, soda
var mineFirst = myFoods.Concat(healthFoods);// 返回序列: grains, proteins, M&Ms, soda, fruits, vegetables, grains, proteins
2. Union() – 串联序列(无重复项)
var healthyFirst = healthFoods.Union(myFoods);// 返回序列: fruits, vegetables, grains, proteins, M&Ms, soda var mineFirst = myFoods.Union(healthFoods);// 返回序列: grains, proteins, M&Ms, soda, fruits, vegetables
3.Zip() – 简单一对一的联接(注:Employee 和Seat是两个对象)
var employees = new List<Employee>
{
new Employee { Id = 13, Name = "John Doe", Salary = 13482.50 },
new Employee { Id = 42, Name = "Sue Smith", Salary = 98234.13 },
new Employee { Id = 99, Name = "Jane Doe", Salary = 32421.12 }
};
var seats = new List<Seat>
{
new Seat { Id = 1, Cost = 42 },
new Seat { Id = 2, Cost = 42 },
new Seat { Id = 3, Cost = 100 },
new Seat { Id = 4, Cost = 100 },
new Seat { Id = 5, Cost = 125 },
new Seat { Id = 6, Cost = 125 },
};
//接下来使用Zip()
var seatingAssignments = employees.Zip(seats, (e, s) => new { EmployeeId = e.Id, SeatId = s.Id });
foreach (var seat in seatingAssignments)
{
Console.WriteLine("雇员: " + seat.EmployeeId + " 预约了座位 " + seat.SeatId);
}
//运行结果(注:一旦到达较短序列的最后一项,它就会立即停止)
雇员: 13 预约了座位1
雇员: 42 预约了座位2
雇员: 99 预约了座位3
4.Join() – 满足条件的联接(注:Employee和Badge是两个对象)
var employees = new List<Employee>
{
new Employee { Id = 13, Name = "John Doe", Salary = 13482.50 },
new Employee { Id = 42, Name = "Sue Smith", Salary = 98234.13 },
new Employee { Id = 99, Name = "Jane Doe", Salary = 32421.12 }
};
var badges = new List<Badge>
{
new Badge { EmployeeId = 10, BadgeNumber = 1 },
new Badge { EmployeeId = 13, BadgeNumber = 2 },
new Badge { EmployeeId = 20, BadgeNumber = 3 },
new Badge { EmployeeId = 25, BadgeNumber = 4 },
new Badge { EmployeeId = 42, BadgeNumber = 5 },
new Badge { EmployeeId = 10, BadgeNumber = 6 },
new Badge { EmployeeId = 13, BadgeNumber = 7 },
};
//接下来使用Join()
var badgeAssignments = employees.Join(badges, e => e.Id, b => b.EmployeeId, (e, b) => new { e.Name, b.BadgeNumber });
foreach (var badge in badgeAssignments)
{
Console.WriteLine("Name: " + badge.Name + " has badge " + badge.BadgeNumber);
}
返回结果:(注:不会返回Jane Doe的信息)
Name: John Doe has badge 2
Name: John Doe has badge 7
Name: Sue Smith has badge 5
5.GroupJoin() – 适用于一对多的条件联接
var badgeAssignments = employees.GroupJoin(b adges, e => e.Id, b => b.EmployeeId, (e, bList) => new { Name = e.Name, Badges = bList.ToList() });
foreach (var assignment in badgeAssignments)
{
Console.WriteLine(assignment.Name + " has badges:");
if (assignment.Badges.Count > 0)
{
foreach (var badge in assignment.Badges) {
Console.WriteLine(" Badge: " + badge.BadgeNumber);
}
}
else {
Console.WriteLine(" No badges.");
}
}
//输出结果
John Doe has badges: Badge: 2 Badge: 7 Sue Smith has badges: Badge: 5 Jane Doe has badges: No badges.