ss请cc来家里钓鱼，鱼塘可划分为n＊m的格子，每个格子有不同的概率钓上鱼，cc一直在坐标(x,y)的格子钓鱼，而ss每分钟随机钓一个格子。问t分钟后他们谁至少钓到一条鱼的概率大？为多少？

include "stdafx.h"

#include<iostream>
#include<vector>

#include<math.h>
#include <iomanip>
using namespace std;

int main()
{
	int n,m, x, y, t;
	while (cin>>n>>m>>x>>y>>t)
	{
		vector<vector<float>> pVec;
		for (int i = 0; i < n; i++)
		{
			vector<float>  vec;
			for (int j = 0; j < m ; j++)
			{
				float p;
				cin >> p;
			//	cout << "内层循环" << endl;
				vec.push_back(p);
			}
			pVec.push_back(vec);
		}


		float ccP = 1-pow((1-pVec[x-1][y-1]),(double)t);
float ssP = 0.0;
		int num = 0;
		for (int x = 0; x < n; x++)
		{
			for (int y = 0; y < m; y++)
			{
				ssP = ssP+ pVec[x][y ];
			
			}
		}

		  ssP = ssP/n/m;
		  ssP = 1 - pow((1 -ssP), (double)t);

		  //设置输出标志

		  ssP = ssP * 100;
		  ccP = ccP * 100;
		  int sp = ssP;
		  int cp = ccP;
		  ssP = sp / 100;
		  ccP = cp / 100;


		  cout << setiosflags(ios::fixed);
			if (ssP >ccP)
			{
				cout << "ss" << endl;
				cout << setprecision(2) << ssP << endl;
			}
			else if (ssP <ccP)
			{
				cout << "cc" << endl;
				cout << setprecision(2) << ccP << endl;
			}
			else
			{
				cout << "equal" << endl;
				cout << setprecision(2)<<ccP << endl;
			}
		


	}
	
	return 0;
}