• P1494 [国家集训队]小Z的袜子


    P1494 [国家集训队]小Z的袜子

    #include<iostream>
    #include<cstdio>
    #include<queue>
    #include<algorithm>
    #include<cmath>
    #include<ctime>
    #include<set>
    #include<map>
    #include<stack>
    #include<cstring>
    #pragma GCC optimize(2)
    #define inf 2147483647
    #define ls rt<<1
    #define rs rt<<1|1
    #define lson ls,nl,mid,l,r
    #define rson rs,mid+1,nr,l,r
    #define N 1000010
    #define For(i,a,b) for(register long long i=a;i<=b;i++)
    #define p(a) putchar(a)
    #define g() getchar()
    
    using namespace std;
    
    long long a[N],cnt[N],b[N],l,r,ql,qr,t,k,w;
    long long n,m,size,num,now,ans1[N],ans2[N];
    struct query{
        long long l,r,id;
    }q[N];
    
    inline bool cmp(query x,query y){
        return (b[x.l]^b[y.l])?b[x.l]<b[y.l]:(b[x.l]&1)?x.r<y.r:x.r>y.r;
    }
    
    void in(long long &x){
        long long y=1;
        char c=g();x=0;
        while(c<'0'||c>'9'){
            if(c=='-')y=-1;
            c=g();
        }
        while(c<='9'&&c>='0'){
            x=(x<<1)+(x<<3)+c-'0';c=g();
        }
        x*=y;
    }
    void o(long long x){
        if(x<0){
            p('-');
            x=-x;
        }
        if(x>9)o(x/10);
        p(x%10+'0');
    }
    
    void update(long long x,long long add){
        now-=cnt[a[x]]*cnt[a[x]];
        cnt[a[x]]+=add;
        now+=cnt[a[x]]*cnt[a[x]];
    }
    
    long long gcd(long long a,long long b){
        return (a%b==0?b:gcd(b,a%b));
    }
    
    int main(){
        in(n);in(m);
        size=sqrt(n);
        num=ceil((double)n/size);
        For(i,1,num)
            For(j,(i-1)*size+1,i*size)
                b[j]=i;
        For(i,1,n)
            in(a[i]);
        For(i,1,m){
            in(q[i].l);in(q[i].r);
            q[i].id=i;
        }
        sort(q+1,q+m+1,cmp);
        l=1;r=0;
        For(i,1,m){
            ql=q[i].l;qr=q[i].r;
            while(l<ql) update(l++,-1);
            while(l>ql) update(--l,1);
            while(r<qr) update(++r,1);
            while(r>qr) update(r--,-1);
            w=now-(qr-ql+1);
            k=(qr-ql+1)*(qr-ql);
            t=gcd(w,k);
            w/=t;
            k/=t;
            ans1[q[i].id]=w;
            ans2[q[i].id]=k;
        }
         For(i,1,m){
             o(ans1[i]);p('/');o(ans2[i]);p('
    ');
         }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/war1111/p/11243067.html
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