• 构建之法--软件工程学习随笔之二


          大三下学期第二周,有时候不得不感叹,在匆忙中时间真的过得好快,一转眼就过去了一周。软件工程的个人项目作业又来了一个新的任务,在上周自动生成30道小学数学加减法题、并能够判断对错的基础上,根据自己情况选择扩展如下的功能:

    • 题目避免重复,可制定打印数量和打印方式。
    • 是否有乘除法。
    • 是否有括号。
    • 数值范围。
    • 加减有无负数。
    • 除法有无余数。
    • 是否支持分数(真分数、假分数...)。
    • 是否支持小树(精确到多少位?)。
    • 打印中每行的间隔。

          在上周的作业中,确实小看了这道题目。上周的作业中,就用了随机数发生器的初始化函数srand和随机函数rand,并且完全没有模块化。显然,在这周的作业中是行不通的。

          因此,这周不得不采取模块化的方式:

          所用函数览表:

    void menu ();              //目录
    void jiben (int m,int n);  //基本算式
    void fenshu (int m,int n); //分数算式
    void zonghe (int m,int n); //综合算式
    int gongyue (int m,int n); //分数求最大公约数
    void huajian(int m,int n); //分数化简

          目录函数:

    void menu ()  //目录
    {
        int a,m = 0,n = 0;
        printf ("	请选择题目难度:
    
    ");
        printf ("    1.基本运算    2.分数运算
        3.综合运算    4.退出程序
    ");
        scanf ("%d",&a);
        switch (a)
        {
        case 1:jiben (m,n);break;
        case 2:fenshu (m,n);break;
        case 3:zonghe (m,n);break;
        default :break;
        }
    }

          采用了switch-case语句。选择所要的操作。

          基本算式函数:

    void jiben (int m,int n)
    {
        int i,x,s,y;
        srand (time (NULL));
        for (i = 0;i < 30;i ++)
        {
            x = rand ()%4;
            m = rand ()%100;
            n = rand ()%100;
            if (x == 0)
            {
                printf ("%d + %d = ",m,n);
                scanf ("%d",&s);
                if (m + n == s)
                    printf ("回答正确。");
                else
                    printf ("回答错误,正确答案是:%d。",m + n);
            }
            else if (x == 1)
            {
                printf ("%d - %d = ",m,n);
                scanf ("%d",&s);
                if (m - n == s)
                    printf ("回答正确。");
                else
                    printf ("回答错误,正确答案是:%d。",m - n);
            }
            else if (x == 2)
            {
                printf ("%d * %d = ",m,n);
                scanf ("%d",&s);
                if (m * n == s)
                    printf ("回答正确。");
                else
                    printf ("回答错误,正确答案是:%d。",m * n);
            }
            else 
            {
                if (n != 0)
                {
                    printf ("%d / %d = ",m,n);
                    scanf ("%d",&s);
                    scanf("%d",&y);
                    if ((m / n == s)&&(m % n == y))
                        printf ("回答正确。");
                    else
                        printf ("回答错误,正确答案是:%d %d。",m / n,m % n);
                }
                else break;
            }
            printf ("请继续做题...
    ");
        }
    }

          基本算式函数可以实现两位数的加、减、乘、除算法,同时,除法可以实现商和余数的结果判断。只有在商和余数都回答正确时才提示答案正确,否则答案错误。在所有的基本算式题目中,如果做出回答,会立即判断正误。如果回答错误,会立即给出正确答案,以供重算、反省。

          分数算式函数:

    void fenshu (int m,int n)  //分数算式函数
    {
        int i,a,s,x,y;
        srand (time (NULL));
        for (i = 0;i < 30;i ++)
        {
            a = rand ()%4;
            m = rand ()%10 + 1;
            n = rand ()%10 + 1;
            x = rand ()%10 + 1;
            y = rand ()%10 + 1;
            if (a == 0)
            {
                printf ("%d/%d + %d/%d = ",m,n,x,y);
                s = gongyue (n,y);
                m = (s / n) * m + (s / y)*x;
                n = s;
                huajian (m,n);
            }
            else if (a == 1)
            {
                printf ("%d/%d - %d/%d = ",m,n,x,y);
                s = gongyue (n,y);
                m = (s / n) * m - (s / y)*x;
                n = s;
                huajian (m,n);
            }
            else if (a == 3)
            {
                printf ("%d/%d * %d/%d = ",m,n,x,y);
                m = m * x;
                n = n * y;
                huajian (m,n);
            }
            else
            {
                printf ("%d/%d / %d/%d = ",m,n,x,y);
                m = m * y;
                n = n * x;
                huajian (m,n);
            }
            printf ("请继续做题...
    ");
        }
    }

          在分数算式函数中,调用了求最大公约数函数和化简函数:

    int gongyue (int m,int n)
    {
        int x = m <n ? m :n;
        while ((x % m) != 0||(x % n) != 0 )
            x ++;
        return x;
    }

          求最大公约数函数中,首先申请一个变量,把所要求公约数的两个分数的分母中较小的一个数放在变量中。做while循环,变量内容逐渐加1,直到该数同时满足整除两个分数的分母时,该变量内容即是最大公约数。并返回最大公约数。

          分数化简函数:

    void huajian (int m,int n)  //分数化简函数
    {
        int a,b,x,y;
        a = abs(m);
        b = abs(n);
        int i = a < b?a : b;
        if (i > 1)
        {
            while (i != 1)
            {
                if ((a%i ==0)&&(b%i == 0))
                {
                    a = a/i;
                    b = b/i;
                }
                i --;
            }
        }
        scanf ("%d%d",&x,&y);
        if (a == x&&b == y)
            printf ("回答正确。");
        else 
        {
            if (b == 1)
            {
                printf ("回答错误。正确答案是:");
                if ((m > 0 &&n < 0)||(m < 0 ||n > 0))
                    printf ("-");
                printf ("%d。",a);
            }
            else
            {
                printf ("回答错误。正确答案是:");
                if ((m > 0 &&n < 0)||(m < 0&&n > 0))
                    printf ("-");
                printf ("%d/%d。",a,b);
            }
        }
    }

          在化简函数中,首先申请四个变量,变量a,b用于保存所要化简分数的分子和分母的绝对值,以便后面判断该分数的符号。变量x,y用于输入数据,以便判断结果的正确性。化简过程是找到需要化简得两数的绝对值较小的数,从该数开始到1过程中,发现某数可以被分子和分母的绝对值整除,则分子和分母同时除该数。直到较小数为一为止。最后,输入结果,判断正误。若错误,给出正确结果。

          综合算式函数:

    void zonghe (int m,int n)
    {
        int i,a,s;
        srand (time (NULL));
        for (i = 0;i <30;i ++)
        {
            a = rand ()%4;
            m = rand ()%20;
            n = rand ()%20;
            if (a == 0)
            {
                printf ("%d + %d ",m,n);
                a = rand ()%4;
                n = rand ()%20;
                if (a == 0)
                    printf ("+ %d = ",n);
                else if (a == 1)
                    printf ("- %d = ",n);
                else if (a == 2)
                    printf ("* %d = ",n);
                else 
                {
                    while (n == 0)
                        n = rand ()%20;
                    printf ("/ %d = ",n);
                }
                scanf ("%d",&s);
                printf ("请继续做题...
    ");
            }
            else if (a == 1)
            {
                printf ("%d - %d ",m,n);
                a = rand ()%4;
                n = rand ()%20;
                if (a == 0)
                    printf ("+ %d = ",n);
                else if (a == 1)
                    printf ("- %d = ",n);
                else if (a == 2)
                    printf ("* %d = ",n);
                else
                {
                    while (n == 0)
                        n = rand ()%20;
                    printf ("/ %d = ",n);
                }
                scanf ("%d",&s);
                printf ("请继续做题...
    ");        
            }
            else if (a == 3)
            {
                printf ("%d * %d ",m,n);
                a = rand ()%4;
                n = rand ()%20;
                if (a == 0)
                    printf ("+ %d = ",n);
                else if (a == 1)
                    printf ("- %d = ",n);
                else if (a == 2)
                    printf ("* %d = ",n);
                else
                {
                    while (n == 0)
                        n = rand ()%20;
                    printf ("/ %d = ",n);
                }
                scanf ("%d",&s);
                printf ("请继续做题...
    ");
            }
            else
            {
                while (n == 0)
                    n = rand ()%20;
                printf ("%d / %d ",m,n);
                a = rand ()%4;
                n = rand ()%20;
                if (a == 0)
                    printf ("+ %d = ",n);
                else if (a == 1)
                    printf ("- %d = ",n);
                else if (a == 2)
                    printf ("* %d = ",n);
                else 
                {
                    while (n == 0)
                        n = rand ()%20;
                    printf ("/ %d = ",n);
                }
                scanf ("%d",&s);
                printf ("请继续做题...
    ");
            }
        }
    
    }

          在该函数中,实现了三个数的综合加、减、乘、除运算。由于时间关系,判断正确过程还没写出,等待下周作业中升级。

          菜单选择界面:

          基本算式界面:

          分数算式界面:

          综合算式界面:

          在这次作业中,实现正负数整数的加、减、乘、除法运算,并判断结果正误。实现了约束数值的取值范围。实现除法的商和余数的计算和判断。实现了分数的加、减、乘、除运算,并判断正误。当然,可能还有一些细节不够完善,还有很多代码非常臃肿,完全可以再细分为几个模块完成,不够简洁。也有一些功能还没有完善,如多项式的结果判断等。期待在下次的作业中做得完美。

          附上完整的代码:

    // yunsuan.cpp : Defines the entry point for the console application.
    //
    
    #include "stdafx.h"
    #include "stdio.h"
    #include "stdlib.h"
    #include "time.h"
    
    void menu ();              //目录
    void jiben (int m,int n);  //基本算式
    void fenshu (int m,int n); //分数算式
    void zonghe (int m,int n); //综合算式
    int gongyue (int m,int n); //分数求最大公约数
    void huajian(int m,int n); //分数化简
    
    int main(int argc, char* argv[])
    {
        menu ();
        return 0;
    }
    
    void menu ()  //目录
    {
        int a,m = 0,n = 0;
        printf ("	请选择题目难度:
    
    ");
        printf ("    1.基本运算    2.分数运算
        3.综合运算    4.退出程序
    ");
        scanf ("%d",&a);
        switch (a)
        {
        case 1:jiben (m,n);break;
        case 2:fenshu (m,n);break;
        case 3:zonghe (m,n);break;
        default :break;
        }
    }
    
    
    void jiben (int m,int n)
    {
        int i,x,s,y;
        srand (time (NULL));
        for (i = 0;i < 30;i ++)
        {
            x = rand ()%4;
            m = rand ()%100;
            n = rand ()%100;
            if (x == 0)
            {
                printf ("%d + %d = ",m,n);
                scanf ("%d",&s);
                if (m + n == s)
                    printf ("回答正确。");
                else
                    printf ("回答错误,正确答案是:%d。",m + n);
            }
            else if (x == 1)
            {
                printf ("%d - %d = ",m,n);
                scanf ("%d",&s);
                if (m - n == s)
                    printf ("回答正确。");
                else
                    printf ("回答错误,正确答案是:%d。",m - n);
            }
            else if (x == 2)
            {
                printf ("%d * %d = ",m,n);
                scanf ("%d",&s);
                if (m * n == s)
                    printf ("回答正确。");
                else
                    printf ("回答错误,正确答案是:%d。",m * n);
            }
            else 
            {
                if (n != 0)
                {
                    printf ("%d / %d = ",m,n);
                    scanf ("%d",&s);
                    scanf("%d",&y);
                    if ((m / n == s)&&(m % n == y))
                        printf ("回答正确。");
                    else
                        printf ("回答错误,正确答案是:%d %d。",m / n,m % n);
                }
                else break;
            }
            printf ("请继续做题...
    ");
        }
    }
    
    int gongyue (int m,int n)
    {
        int x = m <n ? m :n;
        while ((x % m) != 0||(x % n) != 0 )
            x ++;
        return x;
    }
    
    void huajian (int m,int n)  //分数化简函数
    {
        int a,b,x,y;
        a = abs(m);
        b = abs(n);
        int i = a < b?a : b;
        if (i > 1)
        {
            while (i != 1)
            {
                if ((a%i ==0)&&(b%i == 0))
                {
                    a = a/i;
                    b = b/i;
                }
                i --;
            }
        }
        scanf ("%d%d",&x,&y);
        if (a == x&&b == y)
            printf ("回答正确。");
        else 
        {
            if (b == 1)
            {
                printf ("回答错误。正确答案是:");
                if ((m > 0 &&n < 0)||(m < 0 ||n > 0))
                    printf ("-");
                printf ("%d。",a);
            }
            else
            {
                printf ("回答错误。正确答案是:");
                if ((m > 0 &&n < 0)||(m < 0&&n > 0))
                    printf ("-");
                printf ("%d/%d。",a,b);
            }
        }
    }
    
    void fenshu (int m,int n)  //分数算式函数
    {
        int i,a,s,x,y;
        srand (time (NULL));
        for (i = 0;i < 30;i ++)
        {
            a = rand ()%4;
            m = rand ()%10 + 1;
            n = rand ()%10 + 1;
            x = rand ()%10 + 1;
            y = rand ()%10 + 1;
            if (a == 0)
            {
                printf ("%d/%d + %d/%d = ",m,n,x,y);
                s = gongyue (n,y);
                m = (s / n) * m + (s / y)*x;
                n = s;
                huajian (m,n);
            }
            else if (a == 1)
            {
                printf ("%d/%d - %d/%d = ",m,n,x,y);
                s = gongyue (n,y);
                m = (s / n) * m - (s / y)*x;
                n = s;
                huajian (m,n);
            }
            else if (a == 3)
            {
                printf ("%d/%d * %d/%d = ",m,n,x,y);
                m = m * x;
                n = n * y;
                huajian (m,n);
            }
            else
            {
                printf ("%d/%d / %d/%d = ",m,n,x,y);
                m = m * y;
                n = n * x;
                huajian (m,n);
            }
            printf ("请继续做题...
    ");
        }
    }
    
    void zonghe (int m,int n)
    {
        int i,a,s;
        srand (time (NULL));
        for (i = 0;i <30;i ++)
        {
            a = rand ()%4;
            m = rand ()%20;
            n = rand ()%20;
            if (a == 0)
            {
                printf ("%d + %d ",m,n);
                a = rand ()%4;
                n = rand ()%20;
                if (a == 0)
                    printf ("+ %d = ",n);
                else if (a == 1)
                    printf ("- %d = ",n);
                else if (a == 2)
                    printf ("* %d = ",n);
                else 
                {
                    while (n == 0)
                        n = rand ()%20;
                    printf ("/ %d = ",n);
                }
                scanf ("%d",&s);
                printf ("请继续做题...
    ");
            }
            else if (a == 1)
            {
                printf ("%d - %d ",m,n);
                a = rand ()%4;
                n = rand ()%20;
                if (a == 0)
                    printf ("+ %d = ",n);
                else if (a == 1)
                    printf ("- %d = ",n);
                else if (a == 2)
                    printf ("* %d = ",n);
                else
                {
                    while (n == 0)
                        n = rand ()%20;
                    printf ("/ %d = ",n);
                }
                scanf ("%d",&s);
                printf ("请继续做题...
    ");        
            }
            else if (a == 3)
            {
                printf ("%d * %d ",m,n);
                a = rand ()%4;
                n = rand ()%20;
                if (a == 0)
                    printf ("+ %d = ",n);
                else if (a == 1)
                    printf ("- %d = ",n);
                else if (a == 2)
                    printf ("* %d = ",n);
                else
                {
                    while (n == 0)
                        n = rand ()%20;
                    printf ("/ %d = ",n);
                }
                scanf ("%d",&s);
                printf ("请继续做题...
    ");
            }
            else
            {
                while (n == 0)
                    n = rand ()%20;
                printf ("%d / %d ",m,n);
                a = rand ()%4;
                n = rand ()%20;
                if (a == 0)
                    printf ("+ %d = ",n);
                else if (a == 1)
                    printf ("- %d = ",n);
                else if (a == 2)
                    printf ("* %d = ",n);
                else 
                {
                    while (n == 0)
                        n = rand ()%20;
                    printf ("/ %d = ",n);
                }
                scanf ("%d",&s);
                printf ("请继续做题...
    ");
            }
        }
    
    }
  • 相关阅读:
    [JS11] 状态栏滚动
    [JS10] 获取时间
    [JS9] document's bgColor改变背景颜色
    [JS8] 显示从(0,0)到(0,0)的坐标
    [JS7] 显示从0到99的100个数字
    使用StringBuilder或StringBuffer简单优化
    启动一个线程的三种方法
    设置IE浏览器指定的功能
    jquery 判断元素是否存在于数组中
    Hibernate validator验证
  • 原文地址:https://www.cnblogs.com/visionming/p/5277056.html
Copyright © 2020-2023  润新知