• 9-22考试题目 结题报告


    const letter=['0'..'9']+['a'..'f']; 
          inf='encode.in';
          ouf='encode.out';
    var
            a:array [1..9,1..32] of longint;
            f:array [1..33,0..100] of longint;
            pa:array [1..33,0..100] of longint;
            ans,m:string;
    
            procedure getstr(var s:string);
            var ch:char;
            begin
            repeat
                    read(ch);
                    until ch in letter;
                    s:='';
                    repeat
                    case ch of
                    '0':s:=s+'0000';
                    '1':s:=s+'0001';
                    '2':s:=s+'0010';
                    '3':s:=s+'0011';
                    '4':s:=s+'0100';
                    '5':s:=s+'0101';
                    '6':s:=s+'0110';
                    '7':s:=s+'0111';
                    '8':s:=s+'1000';
                    '9':s:=s+'1001';
                    'a':s:=s+'1010';
                    'b':s:=s+'1011';
                    'c':s:=s+'1100';
                    'd':s:=s+'1101';
                    'e':s:=s+'1110';
                    'f':s:=s+'1111';
            end;
            if eoln then break;
            read(ch);
            until not (ch in letter);
            end;
    
            procedure init;
            var p,q:longint;
            st:string;
    
            begin
                    assign(input,inf);
                    reset(input);
                    for p:=1 to 9 do
                    begin
                    getstr(st);
                    while length(st)<32 do st:='0'+st;
                    for q:=1 to 32 do
                    a[p,q]:=ord(st[33-q])-ord('0');
                    end;
            close(input);
            fillchar(f,sizeof(f),$ff);
            end;
    
            function getsum(x,y,num:longint):longint;
            var tmp,u               :longint;
            begin
                    tmp:=y;
                    for u:=1 to 8 do
                    tmp:=tmp+(a[u,x] xor num);
                    getsum:=tmp;
            end;
    
            procedure getvalue(x,y:longint);
            var now,num:longint;
            begin
                    if f[x,y]<>-1 then exit;
                    if x>32 then begin
                    f[x,y]:=1;
                    exit;
                    end;
                    f[x,y]:=0;
                    for num:=0 to 1 do begin
                    now:=getsum(x,y,num);
                    if now and 1<>a[9,x] xor num then continue;
                    getvalue(x+1,now shr 1);
                    if f[x+1,now shr 1]=1 then begin
                    f[x,y]:=1;
                    pa[x,y]:=num;
                    break;
                    end;
                    end;
            end;
    
            procedure getans;
            var p,q:longint;
            begin
                    ans:='';
                    p:=1;
                    q:=0;
                    while p<=32 do begin
                            ans:=chr(48+pa[p,q])+ans;
                            q:=getsum(p,q,pa[p,q]) shr 1;
                            inc(p);
                    end;
            end;
    
            procedure main;
            var tmp:string;
            begin
                    getvalue(1,0);
                    getans;
                    m:='';
                    while ans<>'' do begin
                    tmp:=copy(ans,1,4);
                    if tmp='0000' then m:=m+'0' else
                    if tmp='0001' then m:=m+'1' else
                    if tmp='0010' then m:=m+'2' else
                    if tmp='0011' then m:=m+'3' else
                    if tmp='0100' then m:=m+'4' else
                    if tmp='0101' then m:=m+'5' else
                    if tmp='0110' then m:=m+'6' else
                    if tmp='0111' then m:=m+'7' else
                    if tmp='1000' then m:=m+'8' else
                    if tmp='1001' then m:=m+'9' else
                    if tmp='1010' then m:=m+'a' else
                    if tmp='1011' then m:=m+'b' else
                    if tmp='1100' then m:=m+'c' else
                    if tmp='1101' then m:=m+'d' else
                    if tmp='1110' then m:=m+'e' else
                    if tmp='1111' then m:=m+'f';
                    delete(ans,1,4);
                    end;
                    while (length(m)>1) and (m[1]='0') do delete(m,1,1);
                    assign(output,ouf);
                    rewrite(output);
                    writeln(m);
                    close(output);
            end;
    
            begin
                    init;
                    main;
            end.
    const 
            maxn=1000;
            maxt=1100;
            inf='work.in';
            ouf='work.out';
    var 
            t,a,b :array [0..maxn] of longint;
            f:array [0..maxt+1] of longint;
            n,start:longint;
    
    procedure init;
    var p:longint;
    begin
            start:=maxt;
            assign(input,inf);
            reset(input);
            readln(n);
            for p:=1 to n do begin
                readln(t[p],a[p],b[p]);
                if a[p]<start then start:=a[p];
            end;
        close(input);
    end;
    
    procedure main;
    var 
        i,j:longint;
        find:boolean;
    begin
        fillchar(f,sizeof(f),$ff);
        f[start]:=0;
        for i:=start to maxt do
        if f[i]<>-1 then begin
            find:=false;
            for j:=1 to n do
                if (a[j]<=i) and (i+t[j]<=b[j]) then begin
                find:=true;
                if (f[i+t[j]]=-1) or (f[i+t[j]]>f[i]+t[j]) then
                f[i+t[j]]:=f[i]+t[j];
            end;
            if not find then
            if (f[i+1]=-1) or (f[i+1]>f[i]) then f[i+1]:=f[i];
        end;
        assign(output,ouf);
        rewrite(output);
        writeln(f[maxt]);
        close(output);
    end;
    
    begin
        init;
        main;
    end.

     喜欢就收藏一下,vic私人qq:1064864324,加我一起讨论问题,一起进步^-^

  • 相关阅读:
    设计模式:单一职责原则
    多线程的创建
    Android开发基础(java)14
    面向对象编程的思想(6)
    面向对象编程的思想(5)未完成
    面向对象编程的思想(4)
    面向对象编程的思想(3)
    面向对象编程的思想(2)
    面向对象编程的思想(1)
    GDB 命令详细解释
  • 原文地址:https://www.cnblogs.com/victorslave/p/4830407.html
Copyright © 2020-2023  润新知