• poj 1637 Sightseeing tour 混合欧拉 最大流


    #include <cstdio>
    #include <vector>
    #include <queue>
    #include <cstring>
    using namespace std;
    #define maxn 230
    #define INF 100000
    struct Edge
    {
    	int from, to, cap, flow;
    };
    
    int n, m, s, t;
    vector<Edge> edges;    // 边数的两倍
    vector<int> G[maxn];   // 邻接表,G[i][j]表示结点i的第j条边在e数组中的序号
    bool vis[maxn];        // BFS使用
    int d[maxn];           // 从起点到i的距离
    int cur[maxn];         // 当前弧指针
    int in[maxn],out[maxn];
    int min(int a,int b)
    {
    	if(a<b) return a;
    	else return b;
    }
    void AddEdge(int from, int to, int cap)
    {
    	int len;
    	Edge temp;
    	temp.from=from;temp.to=to;temp.cap=cap;temp.flow=0;
    	edges.push_back(temp);
    	temp.from=to;temp.to=from;temp.cap=0;temp.flow=0;
        edges.push_back(temp);
        len = edges.size();
        G[from].push_back(len-2);
        G[to].push_back(len-1);
    }
    bool BFS()
    {
    	memset(vis, 0, sizeof(vis));
        queue<int> Q;
        Q.push(s);
        vis[s] = 1;
        d[s] = 0;
        while(!Q.empty())
    	{
    		int x = Q.front(); Q.pop();
    		for(int i = 0; i < G[x].size(); i++)
    		{
    			Edge& e = edges[G[x][i]];
    			if(!vis[e.to] && e.cap > e.flow)
    			{
    				vis[e.to] = 1;
    				d[e.to] = d[x] + 1;
    				Q.push(e.to);
    			}
    		}
        }
        return vis[t];
    }
    int DFS(int x, int a)
    {
    	if(x == t || a == 0) return a;
        int flow = 0, f;
        for(int& i = cur[x]; i < G[x].size(); i++)
    	{
    		Edge& e = edges[G[x][i]];
    		if(d[x] + 1 == d[e.to] && (f = DFS(e.to, min(a, e.cap-e.flow))) > 0)
    		{
    			e.flow += f;
    			edges[G[x][i]^1].flow -= f;
    			flow += f;
    			a -= f;
    			if(a == 0) break;
    		}
        }
        return flow;
    }
    int Maxflow()
    {
        int flow = 0;
        while(BFS())
    	{
    		memset(cur, 0, sizeof(cur));
    		flow += DFS(s, INF);
        }
        return flow;
    }
    int main()
    {
        int cas;
        int i;
        int x,y,z;
        scanf("%d",&cas);
        while(cas--)
        {
            scanf("%d%d",&n,&m);
            for(i=0;i<=n+10;i++) G[i].clear();
            memset(in,0,sizeof(in));
            memset(out,0,sizeof(out));
            s=0;t=n+1;
            for(i=1;i<=m;i++)
            {
                scanf("%d%d%d",&x,&y,&z);
                if(z==1)
                {
                    out[x]++;
                    in[y]++;
                }
                else
                {
                    out[x]++;
                    in[y]++;
                    AddEdge(x,y,1);
                }
            }
            int sum=0;
            int flag=1;
            for(i=1;i<=n;i++)
            {
                int ans=in[i]-out[i];
                if(ans<0) ans=-ans;
                if(ans%2==1)
                {
                    flag=0;
                    break;
                }
                if((in[i]-out[i])>0)
                    AddEdge(i,t,(in[i]-out[i])/2);
                else if((in[i]-out[i])<0)
                {
                    AddEdge(s,i,(out[i]-in[i])/2);
                    sum=sum+(out[i]-in[i])/2;
                }
            }
            if(Maxflow()==sum&&flag==1)
                printf("possible
    ");
            else printf("impossible
    ");
        }
        return 0;
    }
    


     

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  • 原文地址:https://www.cnblogs.com/vermouth/p/3710149.html
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