题意:判断链表是否有环。
分析:快慢指针。
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: bool hasCycle(ListNode *head) { ListNode* fast = head; ListNode* slow = head; while(fast && fast -> next){ fast = fast -> next -> next; slow = slow -> next; if(fast == slow) return true; } return false; } };