Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
For example:
Given the below binary tree and sum = 22
,
5 / 4 8 / / 11 13 4 / 7 2 1
return true, as there exist a root-to-leaf path 5->4->11->2
which sum is 22.
解题思路:
递归,JAVA实现如下:
public boolean hasPathSum(TreeNode root, int sum) { if(root==null) return false; if(root.val==sum&&root.left==null&&root.right==null) return true; else return hasPathSum(root.left,sum-root.val)||hasPathSum(root.right,sum-root.val); }