方法1
JsonSerializer serializer = new JsonSerializer();
TextReader tr = new StringReader(text);
JsonTextReader jtr = new JsonTextReader(tr);
UserInfoModel obj = serializer.Deserialize(jtr, typeof(UserInfoModel )) as UserInfoModel ;
注:UserInfoModel 是json对象中参数成员的model
方法2
var obj1 = JObject.Parse(text);
var birth = obj1["birthday"];