本题在于求单价，即为每一天（每200升牛奶）要多少钱，注意超过1000的当做5天，不足200的忽略
#include<iostream>
#include<string>
using namespace std;
class milk {
public:
double p; double average; int vol; int day; string s;
};
int main() {
int T,N,i,redex; cin >> T;
milk m[100]; string s;
while (T--)
{
cin >> N;
for (i = 0; i < N; i++)
{
cin >> m[i].s>>m[i].p>>m[i].vol;
if (m[i].vol >= 1000)
m[i].day = 5; //大于1000的都是5天
else
m[i].day = m[i].vol / 200;
if (m[i].day != 0)
{
m[i].average = m[i].p / m[i].day;
redex = i;
}
}
for (i = 0; i < N; i++)
{
if (m[i].vol < 200)
continue; //容量小于200的忽略忽略
if (m[i].average < m[redex].average)
redex = i;
if (m[i].average == m[redex].average)
{
if (m[i].vol>m[redex].vol) //如果价格相等就比较容量
redex = i;
}
}
cout << m[redex].s << endl;
}
return 0;
}