递归中，调用forEach方法问题

 1     function traverse(objNmae,obj,url){
        url = url || objNmae;
        if(typeof obj === "object" ){
            //for in 方法
            for(let i in obj){
                url += ("=>"+i);
                arguments.callee(i,obj[i],url);
            }
            //forEach 方法
            obj.forEach(function(value,index){
                url += ("=>"+index);
                arguments.callee(index,value,url);
            });
        }else if(typeof obj === "string" || typeof obj === "number"){
            console.log(url+objNmae+":"+obj);
            return;
        }
    }

for in 方法 和forEach方法，方法的功能是同样的，就是遍历一个对象集，并且输出对象中所有末端元素的路径。

接下来我们对下面的这个对象进行遍历

     var itg_data        = [{"itg_num":"1200","itg_category":"rew_gold","itg_reward_num":"1","itg_sum_num":"661","itg_place":"","pic":"/Uploads/game/reward/357203060783037259.png","goods_unit":"u679a","goods_name":null},{"itg_num":"1400","itg_category":"rew_goods","itg_reward_num":"4","itg_sum_num":"656","itg_place":"fresh","pic":"/Uploads/UploadsShop/2017-07-05/595c823c86cf7.jpg","goods_unit":"u679a","goods_name":"u65e0u6297u571fu9e21u86cb"},{"itg_num":"1600","itg_category":"rew_gold","itg_reward_num":"2","itg_sum_num":"555","itg_place":"","pic":"/Uploads/game/reward/357203060783037259.png","goods_unit":"u679a","goods_name":null},{"itg_num":"1800","itg_category":"rew_goods","itg_reward_num":"8","itg_sum_num":"492","itg_place":"fresh","pic":"/Uploads/UploadsShop/2017-07-05/595c823c86cf7.jpg","goods_unit":"u679a","goods_name":"u65e0u6297u571fu9e21u86cb"},{"itg_num":"2500","itg_category":"rew_goods","itg_reward_num":"1","itg_sum_num":"555","itg_place":"fresh","pic":"/Uploads/UploadsShop/2017-06-22/594b602919d9d.jpg","goods_unit":"u53ea","goods_name":"u6bcdu9e21uff08u6563u517buff09"}];

for in 方法

但是在这里 forEach方法会报错，

提示最大调用栈大小超过。但是使用for in 就没有这样的问题

由此可见，forEach在递归中因为，有些对象树过深，对导致其堆栈溢出，forEach不适合用在递归中，可以使用for in