• 游戏中的定时刷新实现方式


    情景1:现在有一个道具商店,共有10个道具可购买。玩家可使用某道具或钻石刷新道具商店中的道具,或者系统会每隔2小时赠送一次刷新次数。

    问题1:如何实现间隔2小时实时刷新?

    from datetime import datetime
    
    def cal_count(timestamp):
        now_dt  = datetime.now()
        base_dt = datetime.fromtimestamp(0)
        last_dt   = datetime.fromtimestamp(timestamp)
     
        count = ((now_dt.date() - base_dt.date()).days*12 + now_dt.hour/2) - 
                ((last_dt.date() - base_dt.date()).days*12 + last_dt.hour/2)
    
        return count
    
    if __name__ == "__main__":
        last_ts = 1433000132
        print cal_count(last_ts)
    View Code

    问题2:刷新后,如何随机出新的10个道具? (注:items=[10001, 10002, 10003, ...], 对应的weight=[1, 2, 3, ...])

    import random
    import time
    import sys
    
    
    def func1(items, weight, times):
        total_weight = sum(weight)
        rand_items   = {}
        all_items    = dict(zip(items, weight))
        for _idx in range(0, times):
            count = 0
            rand  = random.randint(0, total_weight-1)
            for _item, _weight in all_items.iteritems():
                count += _weight
                if rand < count:
                    rand_items[(_item, _weight)] = rand_items.setdefault((_item, _weight), 0) + 1
                    break
    
        return rand_items
    
    def func2(items, weight, times):
        '''
        len(items) == len(weight)
        '''
        _now = time.time()
        if not items:
            return
    
        rand_pools   = []
        rand_items   = {}
        total_weight = sum(weight)
    
        for _idx, _item in enumerate(items):
            rand_pools.extend([_item]*weight[_idx])
    
        for _idx in range(0, times):
            item = random.choice(rand_pools)
            key  = (item, weight[items.index(item)])
            rand_items[key] = rand_items.setdefault(key, 0) + 1
    
        return rand_items
    
    
    def pprint(args, debug=False):
        if debug:
            print args
    
    if __name__ == "__main__": 
        debug  = True
        times  = 10 # rand times
        items  = range(1001, 2001)
        weight = range(100, 100100, 100)
        if len(items) != len(weight):
            pprint( 'data error.', debug )
            sys.exit()
     
        pprint( '
    total items:%s, random times: %s.'%(len(items), times), debug )
    
        _now = time.time()
        rand_items = func1(items, weight, times)
        pprint( "
    func 1 total cost %s seconds."%(time.time()-_now), debug )
        pprint( '
    result:%s.' % sorted(rand_items.iteritems(), key=lambda dt:dt[0], reverse=True) )
    
        _now = time.time()
        rand_items = func2(items, weight, times)
        pprint( "
    func 2 total cost %s seconds."%(time.time()-_now), debug )
        pprint( '
    result:%s'% sorted(rand_items.iteritems(), key=lambda dt:dt[1], reverse=True) )
    View Code

     

  • 相关阅读:
    html 时间区间选择功能
    Django 【settings】数据库设置
    Django forms 定制form字段
    避免js全局变量污染的方法
    js获取路由
    采用遍历的方法获取字符串a在字符串b中的位置
    vue 学习笔记
    Promise
    js常用JSON数据操作
    js 数组遍历方式
  • 原文地址:https://www.cnblogs.com/tangkaixin/p/4543981.html
Copyright © 2020-2023  润新知