You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Note: Given n will be a positive integer.
方法1: 动态规划
方法2: 两个变量(最优解)
方法3: 递归, 最差解
动态规划解法:
public class Solution { public int climbStairs(int n) { if(n == 0 ) { return 0; } if(n == 1){ return 1; } int[] f = new int[n + 1]; f[0] = 1; f[1] = 1; for(int i = 2; i <= n; i++) { f[i] = f[i - 1] + f[i - 2]; } return f[n]; } }
方法二: 两个变量
public class Solution { public int climbStairs(int n) { if(n == 0 ) { return 0; } if(n == 1){ return 1; } int a = 0; int b = 1; int sum = 0; for(int i = 1; i <= n; i++) { sum = a + b; a = b; b = sum; } return sum; } }