逻辑练练手小程序

写个练练手,自己增加要求增加写,至上而下写

# 小程序要求:
# 1.用户可能输入内容中前后多按了空格进行去除
# 2.用户不按规定输入内容返还输入,并给与警告提示
# 3.需要记录用户的信息,输入次数规定3
# 4.提示密码错误,账号错误,或者两者都错
# 4.奖品可选猜对了可以获取2个
# 5.猜的机会有3次
# 6.拿了奖品还能选择能否继续玩
# 7.年龄范围随机 18-15
#思路:
'''
按照功能,
1.多按了空格去除空格,用字符串中的strip方法,

2.有规定次数的引入一个变量进行次数的判断

3.随机数用random函数来解决
'''
# 导入随机函数
import random

# 需要用到的信息

gift_dict = {
    '1': 'Altman',
    '2': 'cat',
    '3': 'dog',
    '4': 'pig'
}
username_pwd_dict = {
    'yangwenyi': 123,
    'nick': 123
}

user_dict = dict()

# 计数

gift_count = 0
age_count = 0
username_count = 0

# 规定年龄

under_age = random.randrange(18, 26)  # 随机数字18-25

# 用户交互 输入账号密码
while username_count < 3:
    user_name = input('请输入你的名字:').strip()
    pwd = int(input('请输入你的密码').strip())
    name_list = username_pwd_dict.keys()
    if pwd == username_pwd_dict.get(user_name):
        print(f'欢迎{user_name}来到猜年龄游戏')
        username_count = 4
    elif user_name in name_list:
        print('账号正确,密码错误')
        username_count += 1
    else:
        username_count += 1
        print('账号错误')
    if username_count == 1:
        print('你已经输错了一次账号密码了还剩2次机会')
    elif username_count == 2:
        print('你已经错两次了,'
              '就剩下1次机会了')
    elif username_count == 3:
        print('机会已经用完了')
        user_name_choose = input('叫爸爸在给你次机会').strip()
        if user_name_choose == '爸爸':
            username_count = 0
        else:
            print('大丈夫能屈能伸,'
                  '你居然这也办不到太让我失望了游戏结束')

    # 用户交互猜年龄
    print('骚年我们开始猜年龄吧年龄18到25,'
          '猜对了有礼物哦,你有三次机会')
    while age_count < 3:
        age_input = input('请输入你的年龄').strip()
        if not age_input.isdigit():
            print('好好输入数字,'
                  '猜对了后面有礼物给你哦')
            age_count += 1
            print(f'你已经浪费了{age_count}次机会了,'
                  f'还剩{3 - age_count}次机会')
            continue
        else:
            if int(age_input) == under_age:
                print('骚年猜对了,来选礼物吧')
                age_count = 4
                gift_count = 0
            elif int(age_input) > under_age:
                print('大了')
                age_count += 1
                print(f'已经使用了{age_count}次机会了,'
                      f'还剩{3 - age_count}次机会')
            else:
                print('小了')
                age_count += 1
                print(f'已经使用了{age_count}次机会了,'
                      f'还剩{3 - age_count}次机会')



        # 与用户交互猜对了拿里面,兼是否还玩
        while age_count == 4 and gift_count != 2:
            gift_chose = input('输入1奖品Altma,'
                               '输入2奖品catt,'
                               '输入3奖品为dog,'
                               '输入4奖品为pig
'
                               '请选择:').strip()
            if not gift_dict.get(gift_chose):
                gift_count += 1
                print(f'你个傻子这也输入错了,礼物较少{gift_count}个')
            else:
                gift_count += 1
                print(f'已经选择{gift_dict[gift_chose]},还有{2 - gift_count}选礼物机会')
                if gift_dict[gift_chose] not in user_dict:
                    user_dict[gift_dict[gift_chose]] = 1
                else:
                    user_dict[gift_dict[gift_chose]] += 1
            if gift_count == 2:
                print(f"恭喜你获得
'Altman'{user_dict.get('Altman',0)}个
"
                      f"'cat'{user_dict.get('cat',0)}个
"
                      f"'dog'{user_dict.get('dog', 0)}个
"
                      f"'pig'{user_dict.get('pig', 0)}个")   #get函数没找到返回,0
                age_count = 3

        # 与用户交互要不要继续

        while age_count == 3:
            age_chose = input('输入小哥哥我们接着游戏,输入我不玩了结束游戏
'
                              '请输入')
            if age_chose == '小哥哥':
                age_count = 0
            elif age_chose == '我不玩了':
                age_count = 100
                print('拜拜')
            else:
                print('好好输入')