Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
题解:参见http://www.cnblogs.com/sunshineatnoon/p/3825032.html
代码如下:
1 /** 2 * Definition for singly-linked list. 3 * class ListNode { 4 * int val; 5 * ListNode next; 6 * ListNode(int x) { 7 * val = x; 8 * next = null; 9 * } 10 * } 11 */ 12 public class Solution { 13 public boolean hasCycle(ListNode head) { 14 ListNode p1 = head; 15 ListNode p2 = head; 16 17 while(p2 != null){ 18 p1 = p1.next; 19 p2 = p2.next; 20 if(p2 != null) 21 p2 = p2.next; 22 else 23 return false; 24 if(p1 == p2) 25 return true; 26 } 27 return false; 28 } 29 }