package com.roocon.thread.t2; public class Demo1 extends Thread { public Demo1(String name){ super(name); } @Override public void run() { while(true){ System.out.println(getName()+"线程执行了"); try { Thread.sleep(1000); } catch (InterruptedException e) { e.printStackTrace(); } } } public static void main(String[] args) { Demo1 d1 = new Demo1("first-thread"); Demo1 d2 = new Demo1("second-thread"); d1.start(); d2.start(); d1.interrupt(); } }
运行结果:
first-thread线程执行了 first-thread线程执行了 second-thread线程执行了 java.lang.InterruptedException: sleep interrupted at java.lang.Thread.sleep(Native Method) at com.roocon.thread.t2.Demo1.run(Demo1.java:17) second-thread线程执行了 first-thread线程执行了 second-thread线程执行了 first-thread线程执行了
first-thread并没有立即被中断!
再看一个例子:
package com.roocon.thread.t2; public class Demo2 extends Thread { public Demo2(String name){ super(name); } @Override public void run() { try { while(true){ System.out.println(getName()+"线程执行了"); Thread.sleep(1000); } } catch (InterruptedException e) { e.printStackTrace(); } } public static void main(String[] args) { Demo2 d1 = new Demo2("first-thread"); d1.start(); d1.interrupt(); } }
运行结果:
first-thread线程执行了
java.lang.InterruptedException: sleep interrupted
at java.lang.Thread.sleep(Native Method)
at com.roocon.thread.t2.Demo2.run(Demo2.java:17)
first-thread线程被中断了!
再看一个例子:
package com.roocon.thread.t2; public class Demo2 extends Thread { public Demo2(String name){ super(name); } @Override public void run() { while (!interrupted()){ try { System.out.println(getName()+"线程执行了"); Thread.sleep(100); } catch (InterruptedException e) { e.printStackTrace(); } } } public static void main(String[] args) { Demo2 d1 = new Demo2("first-thread"); d1.start(); Demo2 d2 = new Demo2("second-thread"); d2.start(); d1.interrupt(); } }
输出结果:
second-thread线程执行了 second-thread线程执行了 second-thread线程执行了 second-thread线程执行了 second-thread线程执行了 second-thread线程执行了 second-thread线程执行了
以上输出说明,first-thread也正常的结束了。
总结:
调用interrupt()方法,立刻改变的是中断状态,但如果不是在阻塞态,就不会抛出异常;如果在进入阻塞态后,中断状态为已中断,就会立刻抛出异常。
interrupt方法有待深入研究。
补充:stop方法:它不会释放线程占有的资源,只是让它一直等待下去。--已过时。