我们知道,python中的字符串分普通字符串和unicode字符串,一般从数据库中读取的字符串会自动被转换为unicode字符串
下面回到重点,使用json.dumps时,一般的用法为:
>>> obj={"name":"测试"}
>>> json.dumps(obj)
'{"name": "\u6d4b\u8bd5"}'
>>> print json.dumps(obj)
{"name": "u6d4bu8bd5"}
>>> json.dumps(obj).encode("utf-8")
'{"name": "\u6d4b\u8bd5"}'
可以看到这里输出的字符串为普通字符串,但是里面的内容却是unicode字符串的内容,即使对结果进行encode("utf-8") ,因为这个字符串本身就已经编码过了,所有进行encode不会有变化
要想得到字符串的真实表示,需要用到参数ensure_ascii=False(默认为True):
>>> json.dumps(obj,ensure_ascii=False)
'{"name": "xe6xb5x8bxe8xafx95"}'
>>> print json.dumps(obj,ensure_ascii=False)
{"name": "测试"}
坑:试试下面的用法(比如key是从数据库中读取的,则会以unicode字符串形式存在):
>>> key=u"name"
>>> obj={key:"测试"}
>>> json.dumps(obj,ensure_ascii=False)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib64/python2.6/json/__init__.py", line 237, in dumps
**kw).encode(obj)
File "/usr/lib64/python2.6/json/encoder.py", line 368, in encode
return ''.join(chunks)
UnicodeDecodeError: 'ascii' codec can't decode byte 0xe6 in position 1: ordinal not in range(128)
这是因为key和value不能以混合普通字符串和unicode字符串的形式存在
改成下面则正常了(同时为普通字符串或同时为unicode字符串):
>>> key=u"name"
>>> obj={key:u"测试"}
>>> json.dumps(obj,ensure_ascii=False)
u'{"name": "u6d4bu8bd5"}'
>>> obj={key.encode("utf-8"):u"测试".encode("utf-8")}
>>> json.dumps(obj,ensure_ascii=False)
'{"name": "xe6xb5x8bxe8xafx95"}'
另外说说还有一个参数default
考虑下面的场景:
>>> class Data:
... def __init__(self):
... self.name = ""
... self.detail = ""
...
>>> data=Data()
>>> data.name="名字"
>>> data.detail="细节"
>>> obj={"data":data}
>>> json.dumps(obj,ensure_ascii=False)
会报下面的异常:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib64/python2.6/json/__init__.py", line 237, in dumps
**kw).encode(obj)
File "/usr/lib64/python2.6/json/encoder.py", line 367, in encode
chunks = list(self.iterencode(o))
File "/usr/lib64/python2.6/json/encoder.py", line 309, in _iterencode
for chunk in self._iterencode_dict(o, markers):
File "/usr/lib64/python2.6/json/encoder.py", line 275, in _iterencode_dict
for chunk in self._iterencode(value, markers):
File "/usr/lib64/python2.6/json/encoder.py", line 317, in _iterencode
for chunk in self._iterencode_default(o, markers):
File "/usr/lib64/python2.6/json/encoder.py", line 323, in _iterencode_default
newobj = self.default(o)
File "/usr/lib64/python2.6/json/encoder.py", line 344, in default
raise TypeError(repr(o) + " is not JSON serializable")
TypeError: <__main__.Data instance at 0x11e87e8> is not JSON serializable
这是因为json.dumps不知道如何对Data对象进行序列化,需要定义一个函数,并赋给参数default:
>>> def convert_to_builtin_type(obj):
... d = {}
... d.update(obj.__dict__)
... return d
...
>>> json.dumps(obj,ensure_ascii=False, default=convert_to_builtin_type)
'{"data": {"name": "xe5x90x8dxe5xadx97", "detail": "xe7xbbx86xe8x8ax82"}}'
>>> print json.dumps(obj,ensure_ascii=False, default=convert_to_builtin_type)
{"data": {"name": "名字", "detail": "细节"}}
def convert_to_builtin_type(obj):
d = {}
d.update(obj.__dict__)
return d