A

On a planet far away from Earth, one year is composed of 12 months, and each month always consists of 30 days.

Also on that planet, there are 5 days in a week, which are Monday, Tuesday, Wednesday, Thursday and Friday. That is to say, if today is Monday, then tomorrow will be Tuesday, the day after tomorrow will be Wednesday. After 3 days it will be Thursday, after 4 days it will be Friday, and after 5 days it will again be Monday.

Today is the d_1d1​-th day in the m_1m1​-th month of year y_1y1​. Given the day of today on that planet, what day will it be (or was it) on the d_2d2​-th day in the m_2m2​-th month of year y_2y2​ on that planet?

Input

There are multiple test cases. The first line of the input contains an integer TT (about 100), indicating the number of test cases. For each test case:

The first line contains three integers y_1y1​, m_1m1​, d_1d1​ (2000 le y_1 le 10^92000≤y1​≤109, 1 le m_1 le 121≤m1​≤12, 1 le d_1 le 301≤d1​≤30) and a string ss, indicating the date and day of today on that planet. It's guaranteed that ss is either "Monday", "Tuesday", "Wednesday", "Thursday" or "Friday".

The second line contains three integers y_2y2​, m_2m2​ and d_2d2​ (2000 le y_2 le 10^92000≤y2​≤109, 1 le m_2 le 121≤m2​≤12, 1 le d_2 le 301≤d2​≤30), indicating the date whose day we want to know.

Output

For each test case output one line containing one string, indicating the day of the d_2d2​-th day in the m_2m2​-th month of year y_2y2​ on that planet.

Sample Input

4
2019 5 12 Monday
2019 5 14
2019 5 12 Tuesday
2019 12 30
2019 5 12 Friday
1000000000 1 1
1000000000 1 1 Wednesday
2019 5 12

Sample Output

Wednesday
Friday
Thursday
Thursday

代码     ps:只需要看day,与year和month无关

 1 #include<iostream>
 2 using namespace std;
 3 int main(){
 4     int t;
 5     int y,m,d;
 6     int y1,m1,d1;
 7     char s[10];
 8     scanf("%d",&t);
 9     while(t--){
10         scanf("%d %d %d %s",&y,&m,&y,s);
11         scanf("%d %d %d",&y1,&m1,&y1);
12         int n=(y1-y)%5;
13         int k;
14         if(s[0]=='M') k=0;
15         else if(s[0]=='T'&&s[1]=='u') k=1;
16         else if(s[0]=='W') k=2;
17         else if(s[0]=='T'&&s[1]=='h') k=3;
18         else if(s[0]=='F') k=4;
19         if(n<=0) k=(k+5+n)%5;
20         else k=(k+n)%5;
21         if(k==0) printf("Monday
");
22         else if(k==1) printf("Tuesday
");
23         else if(k==2) printf("Wednesday
");
24         else if(k==3) printf("Thursday
");
25         else if(k==4) printf("Friday
");
26     }
27 }