• [Swift]LeetCode1275. 找出井字棋的获胜者 | Find Winner on a Tic Tac Toe Game


    ★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
    ➤微信公众号:山青咏芝(let_us_code)
    ➤博主域名:https://www.zengqiang.org
    ➤GitHub地址:https://github.com/strengthen/LeetCode
    ➤原文地址:https://www.cnblogs.com/strengthen/p/12151541.html
    ➤如果链接不是山青咏芝的博客园地址,则可能是爬取作者的文章。
    ➤原文已修改更新!强烈建议点击原文地址阅读!支持作者!支持原创!
    ★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★

    Tic-tac-toe is played by two players A and B on a 3 x 3 grid.

    Here are the rules of Tic-Tac-Toe:

    Players take turns placing characters into empty squares (" ").
    The first player A always places "X" characters, while the second player B always places "O" characters.
    "X" and "O" characters are always placed into empty squares, never on filled ones.
    The game ends when there are 3 of the same (non-empty) character filling any row, column, or diagonal.
    The game also ends if all squares are non-empty.
    No more moves can be played if the game is over.
    Given an array moves where each element is another array of size 2 corresponding to the row and column of the grid where they mark their respective character in the order in which A and B play.

    Return the winner of the game if it exists (A or B), in case the game ends in a draw return "Draw", if there are still movements to play return "Pending".

    You can assume that moves is valid (It follows the rules of Tic-Tac-Toe), the grid is initially empty and A will play first.

    Example 1:

    Input: moves = [[0,0],[2,0],[1,1],[2,1],[2,2]]
    Output: "A"
    Explanation: "A" wins, he always plays first.
    "X " "X " "X " "X " "X "
    " " -> " " -> " X " -> " X " -> " X "
    " " "O " "O " "OO " "OOX"
    Example 2:

    Input: moves = [[0,0],[1,1],[0,1],[0,2],[1,0],[2,0]]
    Output: "B"
    Explanation: "B" wins.
    "X " "X " "XX " "XXO" "XXO" "XXO"
    " " -> " O " -> " O " -> " O " -> "XO " -> "XO "
    " " " " " " " " " " "O "
    Example 3:

    Input: moves = [[0,0],[1,1],[2,0],[1,0],[1,2],[2,1],[0,1],[0,2],[2,2]]
    Output: "Draw"
    Explanation: The game ends in a draw since there are no moves to make.
    "XXO"
    "OOX"
    "XOX"
    Example 4:

    Input: moves = [[0,0],[1,1]]
    Output: "Pending"
    Explanation: The game has not finished yet.
    "X "
    " O "
    " "
     

    Constraints:

    1 <= moves.length <= 9
    moves[i].length == 2
    0 <= moves[i][j] <= 2
    There are no repeated elements on moves.
    moves follow the rules of tic tac toe.


    A 和 B 在一个 3 x 3 的网格上玩井字棋。

    井字棋游戏的规则如下:

    玩家轮流将棋子放在空方格 (" ") 上。
    第一个玩家 A 总是用 "X" 作为棋子,而第二个玩家 B 总是用 "O" 作为棋子。
    "X" 和 "O" 只能放在空方格中,而不能放在已经被占用的方格上。
    只要有 3 个相同的(非空)棋子排成一条直线(行、列、对角线)时,游戏结束。
    如果所有方块都放满棋子(不为空),游戏也会结束。
    游戏结束后,棋子无法再进行任何移动。
    给你一个数组 moves,其中每个元素是大小为 2 的另一个数组(元素分别对应网格的行和列),它按照 A 和 B 的行动顺序(先 A 后 B)记录了两人各自的棋子位置。

    如果游戏存在获胜者(A 或 B),就返回该游戏的获胜者;如果游戏以平局结束,则返回 "Draw";如果仍会有行动(游戏未结束),则返回 "Pending"。

    你可以假设 moves 都 有效(遵循井字棋规则),网格最初是空的,A 将先行动。

    示例 1:

    输入:moves = [[0,0],[2,0],[1,1],[2,1],[2,2]]
    输出:"A"
    解释:"A" 获胜,他总是先走。
    "X " "X " "X " "X " "X "
    " " -> " " -> " X " -> " X " -> " X "
    " " "O " "O " "OO " "OOX"
    示例 2:

    输入:moves = [[0,0],[1,1],[0,1],[0,2],[1,0],[2,0]]
    输出:"B"
    解释:"B" 获胜。
    "X " "X " "XX " "XXO" "XXO" "XXO"
    " " -> " O " -> " O " -> " O " -> "XO " -> "XO "
    " " " " " " " " " " "O "
    示例 3:

    输入:moves = [[0,0],[1,1],[2,0],[1,0],[1,2],[2,1],[0,1],[0,2],[2,2]]
    输出:"Draw"
    输出:由于没有办法再行动,游戏以平局结束。
    "XXO"
    "OOX"
    "XOX"
    示例 4:

    输入:moves = [[0,0],[1,1]]
    输出:"Pending"
    解释:游戏还没有结束。
    "X "
    " O "
    " "
     

    提示:

    1 <= moves.length <= 9
    moves[i].length == 2
    0 <= moves[i][j] <= 2
    moves 里没有重复的元素。
    moves 遵循井字棋的规则。

  • 相关阅读:
    线性Softmax分类器实战
    线性SVM分类器实战
    今日心得:读书
    今日心得:正能量
    Excel导出POI
    mysql数据库操作命令
    git常用命令
    list对象 利用Map去除对象中字段的重复
    SpringMVC 利用POI的Excel导出
    利用ajax进行页面加载进行信息展示时,一直不提加载,转圈,不反回问题。
  • 原文地址:https://www.cnblogs.com/strengthen/p/12151541.html
Copyright © 2020-2023  润新知